Answer: 1. x = -2(y - 4)² + 1
2. x = -y² + 5
3. y = -5(x + 1)² + 2
<u>Step-by-step explanation:</u>
Notes: The vertex formula of a parabola is x = a(y - k)² + h or y = a(x - h)² + k
- (h, k) is the vertex
- p is the distance from the vertex to the focus
1)
Now input a = -2 and (h, k) = (1, 4) into the equation x = a(y - k)² + h
x = -2(y - 4)² + 1
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2)
Now input a = -1 and (h, k) = (5, 0) into the equation x = a(y - k)² + h
x = -1(y - 0)² + 5 → x = -y² + 5
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3)
Now input a = -5 and (h, k) = (-1, 2) into the equation y = a(x - h)² + k
y = -5(x + 1)² + 2
Assuming that the triangles are congruent, you can just look at the parts on each triangle to find the parts on the other triangle. The answers are yes, yes, and no. The triangles are obviously not drawn to scale, so just remember to never rely on it being so.
1/2 ÷ 1/2
= 1/2 ÷ 2/1
= 1/2 × 2/1
= 2/2
= 1
I’m assuming you want to know the values of x and y. If so x=8 and y=2
The derivative, f'(x) = 6x^2+1, is never negative, so f(x) is monotonic, hence invertible.
f'(-2) = 6(-2)²+1 = 25
If point (-2, -26) is on the graph of function f(x), and the slope is 25 there, then (-26, -2) is on the graph of f⁻¹(x), and the slope is 1/25 there. The equation of the tangent line throught that point can be written in point-slope form as
... y +2 = (1/25)(x +26)
