Answer:
6.75 m/s²
Explanation:
The following data were obtained from the question:
Mass (m) of object = 40 Kg
Force applied (Fₐ) = 300 N
Force of friction (Fբ) = 30 N
Acceleration (a) =?
Next, we shall determine the net force acting on the mass. This can be obtained as follow:
Force applied (Fₐ) = 300 N
Force of friction (Fբ) = 30 N
Net force (Fₙ) =?
Fₙ = Fₐ – Fբ
Fₙ = 300 – 30
Fₙ = 270 N
Thus, the net force acting on the mass is 270 N.
Finally, we shall determine acceleration of the mass. This can be obtained as follow:
Mass (m) of object = 40 Kg
Net force (Fₙ) = 270 N
Acceleration (a) =?
Net force = mass × acceleration
Fₙ = m × a
270 = 40 × a
Divide both side by 40
a = 270 / 40
a = 6.75 m/s²
Therefore, the acceleration of the mass is 6.75 m/s²
