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dexar [7]
3 years ago
6

60 POINT!!!!!!

Physics
2 answers:
Genrish500 [490]3 years ago
8 0
You in college stop cheating
Elanso [62]3 years ago
5 0
To identify a pure liquid substance using the physical properties of solubility, density, and boiling point. The physical properties of a pure substance can be measured without changing the composition of the substance. In this experiment you will learn techniques for determining solubility, density, and boiling point.
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Describe why cars are inefficient machines in terms of thermodynamics.
Alina [70]

Cars are the mechanical device which convert chemical energy of fuel into mechanical energy, the engine used in the automobiles car are very inefficient, they can only convert 30-40% of chemical energy of fuel into mechanical energy, since thermodynamics is the branch of science that deals with the conversion of energy, thus due to poor conversion rate of chemical energy into mechanical energy, cars are known as inefficient machine.

6 0
3 years ago
Read 2 more answers
A car accelerates from 10m/s to 20m/s over a distance of 80m. What is its acceleration?
Lina20 [59]

Answer:

0.125m/s^2

Explanation:

20-10=10

10 divided by 80=0.125m/s^2

5 0
3 years ago
Which of the following Illustrates 2 resistors in a series circult? A, B, C, D.​
Kaylis [27]

Answer:

It's either B or D, I'm not positive which it is

Explanation:

6 0
2 years ago
Can you please answer qeastion
notsponge [240]

Answer:

the mantel

Explanation:

yeeeeaaaaaaa

8 0
3 years ago
A communications channel has a bandwidth of 4,000 hz and a signal-to-noise ratio (snr of 30 db. what is the maximum possible dat
levacccp [35]
Through Shannon's Theorem, we can calculate the capacity of the communications channel using the value of its bandwidth and signal-to-noise ratio. The capacity, C, can be expressed as 

C = B × log₂(1 + S/N)

where B is the bandwidth of the channel and S/N is its signal-to-noise ratio.

Since the given SN ratio is in decibels, we must first express it as a ratio with no units as

SN (in decibels) = 10 × log (S/N)
30 = 10log(S/N)
log(S/N) = 3
S/N = 10³ = 1000

Now that we have S/N, we can solve for its capacity (in bits per second) as 

C = 4000 × log₂(1 + 1000) 
C = 39868.91 bps

Thus, the maximum capacity of the channel is 39868 bps or 40 kbps.

Answer: 40 kbps

 
4 0
3 years ago
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