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Furkat [3]
3 years ago
5

CaCO3(s)+2H*(aq) →Ca2+ (aq)+H2001+CO262)

Chemistry
1 answer:
Effectus [21]3 years ago
8 0

Answer:CO2(g) will be formed at a faster rate in experiment 2 because more H+ particles can react per unit time

Explanation:

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How are elements in the same group similar
Georgia [21]
All the elements in one group have the same number of valence electrons.
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3 years ago
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"you have a mixture made os two substances, one with a higher density than the other. how could you separate the substances in t
shtirl [24]
The correct answer is <span>D) centrifuge the mixture because the substance with the highter density will be pulled to the bottom

When things spin around, like a centrifuge, the centripetal force draws things towards the middle. If you make it a bit like a spiral and put it sideways, then the denser thing will go to the bottom while the less dense ones will remain on the outside. </span>
3 0
4 years ago
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A gas has a volume of 5.00 L at 20.0oC. If the gas is compressed to 4.0 L, what is the new temperature of the gas in Kelvin?
Tatiana [17]

Answer: 234.4K

Explanation:

Given that,

Original volume of gas (V1) = 5.00 L

Original temperature of gas (T1) = 20.0°C

[Convert 20.0°C to Kelvin by adding 273

20.0°C + 273 = 293K]

New volume of gas (V2) = 4.0L

New temperature of gas (T2) = ?

Since volume and temperature are given while pressure is held constant, apply the formula for Charle's law

V1/T1 = V2/T2

5.00L/293K = 4.0L/T2

To get the value of T2, cross multiply

5.00L x T2 = 293K x 4.0L

5.00L•T2 = 1172L•K

Divide both sides by 5.00L

5.00L•T2/5.00L = 1172L•K/5.00L

T2 = 234.4K

Thus, the new temperature of the gas is 234.4 Kelvin

8 0
3 years ago
When a sodium (Na) atom forms an ion so that it looks like a noble gas with a full valence shell, what will its charge be?
Setler79 [48]

Answer:

I believe 1+

Explanation:

when Na loses 1 electron in the outer shell it has 8 valence protons on it's new most outer shell. so now it has 11 protons and 10 electrons. that extra proton (positively charged) adds one extra charge. so +1

5 0
3 years ago
A resting adult requires about 240 ml of pure oxygen/mind and breathes about 12 times every minute. if inhaled air contains 20 p
Dmitry_Shevchenko [17]

12 times breathe give 240 ml of pure O_{2}. Each breathe gives 20 ml of O_{2}.

Let us consider, volume of air per breathe= x ml.

Pure O_{2} from inhaled air= \frac{20}{100}x ml and Pure O_{2} from exhaled air= \frac{16}{100}x ml.

Pure O_{2} from inhaled and exhaled air= 20 ml

So, \frac{20}{100}x + \frac{16}{100}x = 20

Therefore, x = 55.5 ml

So, volume of air per breath= 55.5 ml.


7 0
3 years ago
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