The enthalpy of combustion of 1 mole of benzene is 3169 kJ/mol .
The first step in answering this question is to obtain the balanced thermochemical equation of the reaction. The thermochemical equation shows the amount of heat lost or gained.
The thermochemical equation for the combustion of benzene is;
2 C6H6(l) + 15 O2(g) → 12 CO2(g) + 6 H2O(g) ΔrH° = -3169 kJ/mol
We can see that 1 mole of benzene releases about 3169 kJ/mol of heat.
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Answer:
0.86L.
Explanation:
1mol of Zn has mass of 65.39g . The amount of Zn is 2.5g65.39g/mol=0.038mol
Answer:the 5g would be more dense due to the mass and structure
Of it causing the atoms to expand as heat gets added
Explanation:
Answer: velocity
Explanation: trust me man
