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Tatiana [17]
3 years ago
14

Perimeter is always measured in square units. True False

Mathematics
2 answers:
stiv31 [10]3 years ago
6 0

Answer:

Perimeter is always measured in square units.

true

Step-by-step explanation:

Bingel [31]3 years ago
4 0

false

Step-by-step explanation:

the perimeter is all the sides added up whereas the area is length × width

area is measured in square units not perimeter

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Tell whether the sequence is arithmetic if it is identify the common difference -7,-3,1,5
seraphim [82]
Yes it is an arithmetic sequence because a specific number is being added to each previous number. So starting from -7, if you add 4 you get -3, add 4 again to get 1, add 4 one last time to get 5

So, yes the sequence is arithmetic and the common difference is +4
7 0
3 years ago
A doctor prescribes a 100-mg antibiotic tablet to be taken every eight hours. Just before each tablet is taken, 20% of the drug
zvonat [6]

Answer:

120 mg

Step-by-step explanation:

20% of  100 is 20 so that would be 20mg  plus the 100mg they just took

100+20=120mg

i hope this helps you!

7 0
2 years ago
PLSS ANSWER
icang [17]
The answer is one and five eighths.
7 0
2 years ago
What number two numbers when multiplied equal 24 but when added equal -4
madam [21]
Since it says when Added they are a negative and when multiplied they are positive, we know our two numbers are negative.
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6 and 4
8 and 3
12 and 2
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5 0
3 years ago
Filipo is building a rectangular sandbox . The length of the sandbox is 1 foot longer than twice the width of the sandbox .the p
Alla [95]

Answer:

Part A : D.) 2w + 2(2w+ 1) = 29

Part B : Length of the sandbox is 10 feet.

Step-by-step explanation:

Given,

Perimeter = 29 ft

We need to find the equation for the perimeter and also the length of the sandbox.

Solution,

Let the width of the sandbox be 'w'.

Now as per question said;

The length of the sandbox is 1 foot longer than twice the width of the sandbox.

So we can say that;

Length = 2w+1

Now we know that the perimeter is equal to the sum of twice of length and width.

framing in equation form, we get;

Perimeter = 2(2w+1)+2w

we have given the perimeter, so on substituting the value, we get;

29=2(2w+1)+2w

Hence The equation used to find the width is  29=2(2w+1)+2w.

Now we solve for 'w'.

Applying distributive property, we get;

4w+2+2w=29\\\\6w+2=29

Subtracting both side by '2' we get

6w+2-2=29-2\\\\6w=27

Dividing both side by 6 we get;

\frac{6w}{6}=\frac{27}{6}\\\\w=4.5\ ft

Width of the sandbox = 4.5 ft

Length of the sandbox = 2w+1=2\times4.5 +1 = 9+1=10\ ft

Hence Length of the sandbox is 10 feet.

3 0
3 years ago
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