Answer:
The correct answer is 1.194 J/g.ºC
Explanation:
The heat released by the material is absorbed by the water. We put a minus sign (-) for a released heat and a plus sign (+) for an absorbed heat.
We know the mass of the material (mass mat= 25.0 g) and the mass of water (mass H20= 100.0 g) and the specific heat capacity of water is known (Shw=4.18 J/g.ºC), so we can equal the heat released by the material and the heat absorbed by water y calculate the specific heat capacity of the material (Shm) as follows:
heat released by material = heat absorbed by water
-(mass material x Shm x ΔT)= mass water x Shw x ΔT
-(25.0 g x Shm x (24ºC - 80ºC)= 100.0 g x 4.18 J/g.ºC x (24ºC-20ºC)
25.0 g x Shm x (56ºC) = 100.0 g x 4.18 J/g.ºC x 4ºC
⇒Shm= (100.0 g x 4.18 J/g.ºC x 4ºC)/(25.0 g x 56ºC)
Shm= 1.194 J/g.ºC
Answer:
Chromatography
Explanation:
Chromatography is a technique for separating mixtures that involves the use of a moving liquid and filter paper. The solvent travels through the spots on the paper, taking the chemicals away in the opposite direction. If the solvent combination has been properly chosen, each of them will move at a different velocity than the others.
Answer:
Explained below.
Explanation:
In oil rigs, Sacrificial protection is the protection of the steel against corrosion by using magnesium block which is a more reactive metal. This means that steel which is to be protected from corrosion will be the cathode while magnesium block preventing it from corrosion will be the anode and as such the block will be the one to corrode instead.
The mechanism behind this sacrificial protection is that the steel pipe on the rig will be connected to the magnesium block through copper wires and then the magnesium block will donate its electrons to the steel thereby preventing it from rusting. Thus is a reversible reaction and as such, after the steel Iron undergoes oxidization by receiving electrons from the magnesium block, it will be immediately be reduced to iron as depicted in the equation below.
Mg⇌Mg^(2+) + 2e-
Fe^(2+) + 2e-⇌Fe
