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sweet-ann [11.9K]
1 year ago
11

Hydrazine (N₂H₄), a rocket fuel, reacts with oxygen to form nitrogen gas and water vapor. The reaction is represented with the e

quation:
N₂H₄(I) + O₂(g) --->N₂(g) + 2H₂O(g)

At STP, if 4.20L of O₂ reacts with N₂H₄, how many liters of water vapor will be produced?
Chemistry
2 answers:
Vinvika [58]1 year ago
8 0

At STP one mol weighs 22.4L

Moles of O_2

  • 4.2/22.4
  • 2.1/11.2
  • 0.19mol

1 mol.O_2 can create 2mol water

moles of water

  • 2(0.19)
  • 0.38mol

Volume of water

  • 0.38(22.4)
  • 8.512L
seraphim [82]1 year ago
6 0

Answer:

The given equation is:

N2H4(l) + O2(g) → N2(g) + 2H2O(g)

From the periodic table:

  • mass of nitrogen = 14 grams
  • mass of hydrogen = 1 gram
  • mass of oxygen = 16 grams

Therefore:

molar mass of N2H4 = 2(14) + 4(1) = 32 grams

mass of water = 2(1) + 16 = 18 grams

From the balanced equation:

1 moles of N2H4 produces 2 moles of H2O.

32 grams of N2H4 produce 18*2=36 grams of water

To know the mass of N2H4 needed to produce 96 grams of water, all you need to do is cross multiplication as follows:

<h3>mass of N2H4 = (96*32) / 36 = 85.3334 grams</h3>
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Tju [1.3M]

The empirical formula is the same as the molecular formula : C₁₀H₅O₂

<h3>Further explanation</h3>

Given

Molecular formula : C₁₀H₅O₂

Required

The empirical formula

Solution

The empirical formula (EF) is the smallest comparison of atoms of compound forming elements.  

The molecular formula (MF) is a formula that shows the number of atomic elements that make up a compound.  

(empirical formula) n = molecular formula  

<em>(EF)n=MF </em>

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If we divide by the number of moles of Oxygen (the smallest) which is 2 then the moles of Hydrogen will be a decimal number (not whole), which is 2.5, then the empirical formula is the same as the molecular formula

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likoan [24]

Answer:

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Explanation:

assuming no heat loss to the surroundings, all the heat of solution (due to the dissolving process) is absorbed by the same solution and therefore:

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Using tables , can be found that the heat of solution of CaCl2 at 25°C (≈24.7 °C)  is q dis= -83.3 KJ/mol . And the molecular weight is

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Q dis = q dis * n  = q dis * m/M =  -83.3 KJ/mol * 13.1 g/110.9 gr/mol = -9.84 KJ

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Also Qsol = ms * Cs * (T - Ti)

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T=  Ti - Qdis * (ms * Cs )^-1   =24.7 °C - (-9.84 KJ/mol)/[(104 g + 13.1 g)* 4.18 J/g°C] *1000 J/KJ

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