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Yuki888 [10]
3 years ago
7

Multi-Step Conversions (Always go through moles!)

Chemistry
1 answer:
Annette [7]3 years ago
8 0

Mass of water needed : 96.3 g

<h3>Further explanation   </h3>

A mole is a number of particles(atoms, molecules, ions)  in a substance

This refers to the atomic total of the 12 gr C-12  which is equal to 6.02.10²³, so 1 mole = 6.02.10²³ particles  

Can be formulated :

N = n x No

N = number of particles

n = mol

No = 6.02.10²³ = Avogadro's number

moles H₂O=

\tt moles=\dfrac{N}{No}\\\\moles=\dfrac{3.22\times 10^{24}}{6.02\times 10^{23}}\\\\moles=5.35

mass H₂O(MW=18 g/mol) :

\tt mass=moles\times MW\\\\mass=5.35\times 18\\\\mass=96.3~g

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Assoli18 [71]
Is this a multiple choice? Anyways I will just give you a written answer and hopefully it helps.

A: Helium is made up of two electrons held by electromagnetic force to two protons that are inside of a nucleus along with one or two neutrons.
5 0
3 years ago
Pleas help with 2 and 4 for brainliest
Snezhnost [94]

mass of pentane : = 30.303 g

moles of Al₂(CO₃)₃ : = 0.147

<h3>Further explanation</h3>

Given

1. Reaction

C₅H₁₂+8O₂→6H₂O+5CO₂.

45.3 g water

2. 2AlCl₃ + 3MgCO₃ → Al₂(CO₃)₃ + 3MgCl₂

37.2 MgCO₃

Required

mass of pentane

moles of Al₂(CO₃)₃

Solution

1. mol water = 45.3 : 18 g/mol = 2.52

From equation, mol ratio of C₅H₁₂ : H₂O = 1 : 6, so mol pentane :

= 1/6 x mol H₂O

= 1/6 x 2.52

= 0.42

Mass pentane :

= mol x MW

= 0.42 x 72.15 g/mol

= 30.303 g

2. mol MgCO₃ : 37.2 : 84,3139 g/mol = 0.44

mol Al₂(CO₃)₃ :

= 1/3 x mol MgCO₃

= 1/3 x 0.44

= 0.147

4 0
3 years ago
235 92 U &gt;144 56 Ba + 3 1 on
Kobotan [32]

Answer:?

Explanation:

5 0
3 years ago
You carefully weigh out 11.00 g of caco3 powder and add it to 44.55 g of hcl solution. you notice bubbles as a reaction takes pl
Zinaida [17]
The bubbles that were observed after the mixing of the two substances is one of the products of the reaction. It is the carbon dioxide that is produced. To determine the mass of this gas produced, we need to remember the Law of conservation of mass where mass cannot be created or destroyed. With this, we can say that the total mass that goes in a process should be equal to the mass that is goes out of the process no matter what the reaction is. We do as follows:

Mass of reactants = mass of products
11.00 + 44.55 = 51.04 + mass of carbon dioxide
mass of carbon dioxide = 4.51 g
8 0
3 years ago
How many atoms of carbon are in the sample
Serhud [2]
There are six atoms in the carbon
6 0
3 years ago
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