Answer : The limiting reactant is
and the theoretical yield will be 86.45 grams.
Explanation : Given,
Moles of
= 0.483 mole
Moles of
= 0.911 mole
Molar mass of
= 190 g/mole
First we have to calculate the limiting and excess reagent.
The given balanced chemical reaction is,

From the balanced reaction we conclude that
As, 2 moles of
react with 1 mole of 
So, 0.911 moles of
react with
moles of 
From this we conclude that,
is an excess reagent because the given moles are greater than the required moles and
is a limiting reagent and it limits the formation of product.
Now we have to calculate the moles of
.
As, 2 moles of
react to give 1 moles of 
So, 0.911 moles of
react to give
moles of 
Now we have to calculate the mass of
.


Therefore, the theoretical yield will be 86.45 grams.