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denis23 [38]
3 years ago
5

10 points. Solve for g. Will give brainliest to first correct answer 22 (g - 1) = 2g + 8

Mathematics
1 answer:
Harrizon [31]3 years ago
7 0

Answer:

g = 3/2

hope it's helpful ❤❤❤❤❤❤

THANK YOU.

#

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How many solutions does the equation have? 5(w−1)−2=5w+7<br><br>A.0 B.1 C.infinitely many
bogdanovich [222]
5(w - 1) - 2 = 5w + 7
5w - 5 - 2 = 5w + 7
5w - 7 = 5w + 7
5w - 5w = 7 + 7
0 = 14 (incorrect)

there are no solutions to this system...0 solutions
6 0
3 years ago
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PLEASE ANSWER, I HAVE A QUIZ THAT NEEDS TO GET DONE AND I HAVE NO IDEA HOW TO GET THIS!
Oliga [24]
There you go. cube root of smth is just the value to the power of one third.

4 0
3 years ago
Put these numbers from least to greatest value.<br> 22/7 , square root of 3, 16/4, square root of 5
Crank
From least to greatest is  square root of 3, square root of 5, 22/7 , 16/4 
  hope it help

8 0
3 years ago
Evaluate the expression <br> 5.4+ab, if a = 4 and b = 8
dsp73

Answer:

37.4

Step-by-step explanation:

a = 4 and b = 8

change the equation

5.4 + (4) (8)

use P.E.M.D.A.S. and multiply

4*8 = 32

add

5.4 + 32 = 37.4

7 0
3 years ago
Which is the completely factored form of 4x2 28x 49? (x 7)(4x 7) 4(x 7)(x 7) (2x 7)(2x 7) 2(x 7)(x 7)
natima [27]

The completely factored form of 4x^2 + 28x + 49 is given by: Option C: (2x+7)(2x+7)

<h3>How to find the factors of a quadratic expression?</h3>

If the given quadratic expression is of the form ax^2 + bx + c, then its factored form is obtained by two numbers alpha( α ) and beta( β) such that:

b = \alpha + \beta \\ ac =\alpha \times \beta

Then writing b in terms of alpha and beta would help us getting common factors out.

Sometimes, it is not possible to find factors easily, so using the quadratic equation formula can help out without any  trial and error.

For this case, the given quadratic expression is:

4x^2 + 28x + 49

So we've to find two numbers such that:

Their sum = b =  28

Their product = ac = 4\times 49 = 196

We can see that 196 is square of 14, and that 14 added twice forms 28, thus:

14 + 14 = 28

14×14 = 196

Writing b = 28 as sum of 14 twice, we get:

4x^2 + 28x + 49 = 4x^2 + 14x + 14x +49 \\4x^2 + 28x + 49 =  2x(2x+7) + 7(2x + 7)\\4x^2 + 28x + 49  = (2x+7)(2x+7)

Thus, the completely factored form of 4x^2 + 28x + 49 is given by: Option C: (2x+7)(2x+7)

Learn more about factorization of quadratic expression here:

brainly.com/question/26675692

8 0
2 years ago
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