3 years ago

What is the equation a line passes through the points p(2,4) q(-1,3)

1 answer:

4 0

Find slope: (y2-y1)/(x2-x1)
(3-4)/(-1-2) = -1/-3 = 1/3
Y = 1/3x + b
4 = 1/3(2) + b
4 = 2/3 + b, b = 10/3
Y = 1/3x + 10/3

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The points represented by the table lie on a line. How can you find the slope of the line

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Step-by-step explanation:

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3 years ago

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Dvinal [7]

Answer:

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Step-by-step explanation:

$In\: \triangle GFH \: and\; \triangle GJI\\\angle GFH \cong \angle GJI..(each\: 90\degree)\\\angle FGH \cong\angle JGH..(common\: angles)\\\therefore \triangle GFH \sim \triangle GJI..(by \: AA\: postulate)\\\\\therefore \frac{GF}{GJ}=\frac{HF}{IJ}..(By\: c.s.s.t.)\\\\\therefore \frac{4}{8}= \frac{q}{6}\\\\\therefore \frac{1}{2}= \frac{q}{6}\\\\q =\frac{6}{2}\\q= 3 \: units$