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Tom [10]
3 years ago
6

Someone deleted my math question :(... here are some points haha

Mathematics
2 answers:
lana [24]3 years ago
7 0

Answer:

tytty have a good day shhawtayy

Step-by-step explanation:

Alex Ar [27]3 years ago
3 0

Answer:

thanks these help alot

Step-by-step explanation:

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-PLEASE HELP ME WITH THIS <br><br> THANKS TO ALL HELPFUL USERS
Marizza181 [45]
The answer is the first option. 


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3 years ago
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A store sells 8 cans of soup for ​$22. How much would it cost you to buy 9 cans of soup​?It would cost ​$nothing.
puteri [66]
$24.75

this is because 22 ÷ 8 × 9 is equal to 24.75
this is the correct answer
6 0
3 years ago
Lester's Cafe offers two kinds of espresso: single-shot and double-shot. Yesterday afternoon, the cafe sold 80 espressos in all,
bogdanovich [222]

Answer:

64 single-shot espressos

Step-by-step explanation:

Let's say that the cafe sold x single-shot espressos. The total number of espressos sold was 80, and 80% of that total 80 were single-shot. So, we have the equation:

x = 80% * 80

Remember that % just means "out of 100". So, 80% = 80/100:

x = (80/100) * 80 = 6400/100 = 64 single-shot espressos

Hope this helps!

7 0
3 years ago
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Carmen rolls a cube with sides labeled A, B, C, D, E, and F.
Sav [38]
The number of possible outcomes is 29. ! hope this help hun <3
5 0
3 years ago
A sample of 26 offshore oil workers took part in a simulated escape exercise, and their escape time (unit: second) were observed
Anuta_ua [19.1K]

Answer:

t=\frac{370.69-360}{\frac{24.36}{\sqrt{26}}}=2.238  

The degrees of freedom are given by:

df = n-1= 26-1=25

And the p value would be:

p_v =P(t_{25}>2.238)=0.0172  

If we use a 5% of significance level we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significantly higher than 360 second or 6 minutes. We need to be careful since if we use a significance level of 1% the result change

Step-by-step explanation:

Information given

\bar X=370.69 represent the sample mean

s=24.36 represent the sample standard deviation

n=26 sample size  

\mu_o =6*60 =360 s represent the value to verify

z would represent the statistic

p_v represent the p value

Hypothesis to test

We want to check if the true mean is at most 360 seconds, the system of hypothesis would be:  

Null hypothesis:\mu \leq 360  

Alternative hypothesis:\mu > 360  

The statistic for this case would be given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)  

We can replace in formula (1) the info given like this:  

t=\frac{370.69-360}{\frac{24.36}{\sqrt{26}}}=2.238  

The degrees of freedom are given by:

df = n-1= 26-1=25

And the p value would be:

p_v =P(t_{25}>2.238)=0.0172  

If we use a 5% of significance level we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significantly higher than 360 second or 6 minutes. We need to be careful since if we use a significance level of 1% the result change

4 0
3 years ago
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