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wolverine [178]

3 years ago

13

Plz help I really need help

2 answers:

Dominik [7]3 years ago

5 0

Answer: -1/5

Step-by-step explanation:

slope = x/y

when graphed you can subtracted the highest y point (15) to the lowest y point (10) which equals 10, from there you subtract the highest x point (5) from the lowest x point (3) and get 2, however since x is going down this makes it a negative making the 2 into -2, from there you divide -2/10 and get -1/5

siniylev [52]3 years ago

3 0

Answer:

slope is -1

Step-by-step explanation:

x is going down by -1

y is going up by 5

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T+b = 41<br> t = 2b+2<br> Solve for t and b

erastovalidia [21]

Answer: b=13, t=29

Step-by-step explanation:

Substituting the first equation into the second,

$2b+2+b=41\\\\3b+2=41\\\\3b=39\\\\b=13\\\\\implies t=2(13)+2=29$

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Step-by-step explanation:

7 0

3 years ago

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help please <br><br> No links

11Alexandr11 [23.1K]

Answer:

62-0.75x8

Step-by-step explanation

$6=discount

8 tickets

Total=62.00

0.75 multiplied by 8= 6

62-6=56

56 is before the discount

Equation would be 62-0.75x8

8 0

2 years ago

Lorne subtracted 6x3 – 2x + 3 from –3x3 + 5x2 + 4x – 7. Use the drop-down menus to identify the steps Lorne used to find the dif

Novay_Z [31]

Answer: Step 1: Reverse the signs of $6x^3-2x + 3$ expression.

Step 2: Removing parenthesis

Step 3: Grouping like terms

Step 4: Combing like terms

Step 5: Writing the final expression in standard form

Step-by-step explanation: First expression : $6x^3-2x + 3$

Second expression : $-3x^3+5x^2+4x-7$ .

We need to subtract $6x^3-2x + 3$ from $-3x^3+5x^2+4x-7$ .

Step 1: Reverse the signs of $6x^3-2x + 3$ expression.

$(-3x^3+5x^2+4x-7)+(-6x3+2x-3)$

Step 2: Removing parenthesis

$(-3x^3) +5x^2+4x + (-7) + (-6x^3) + 2x + (-3)$

Step 3: Grouping like terms

$[-3x^3) + (-6x^3)] + [4x + 2x] + [(-7) + (-3)] + [5x^2]$

Step 4: Combing like terms

$-9x^3 + 6x + (-10) + 5x^2$

Step 5: Writing the final expression in standard form

$-9x^3 + 5x^2 + 6x-10$

8 0

3 years ago

Read 2 more answers

Solve 5x^2-2=-12 by taking the square root

k0ka [10]

Answer:

x = ±i√2

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Multiplication Property of Equality

Division Property of Equality

Addition Property of Equality

Subtraction Property of Equality<u> </u>

<u>Algebra II</u>

Imaginary root <em>i</em>

<em>i</em> = √-1

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

5x² - 2 = -12

<u>Step 2: Solve for </u><em><u>x</u></em>

[Addition Property of Equality] Add 2 on both sides: 5x² = -10
[Division Property of Equality] Divide 5 on both sides: x² = -2
[Equality Property] Square root both sides: x = ±√-2
Rewrite: x = ±√-1 · √2
Simplify: x = ±i√2

7 0

2 years ago