Answer:
but it was a good time to khow is he
Answer:
the magnitude of the average contact force exerted on the leg is 3466.98 N
Explanation:
Given the data in the question;
Initial velocity of hand v₀ = 5.25 m/s
final velocity of hand v = 0 m/s
time interval t = 2.65 ms = 0.00265 s
mass of hand m = 1.75 kg
We calculate force on the hand F
using equation for impulse in momentum
F × t = m( v - v₀ )
we substitute
F × 0.00265 = 1.75( 0 - 5.25 )
F × 0.00265 = 1.75( - 5.25 )
F × 0.00265 = -9.1875
F = -9.1875 / 0.00265
F = -3466.98 N
Next we determine force on the leg F
Using Newton's third law of motion
for every action, there is an equal opposite reaction;
so, F = - F
we substitute
F = - ( -3466.98 N )
F = 3466.98 N
Therefore, the magnitude of the average contact force exerted on the leg is 3466.98 N
Answer:
The Spring force
Explanation:
The Spring force is a force that is centered around, guess what, springs. Al that the Spring force says is that when a spring is compressed or stretched out, it will return to the state that it was originally in, and because it is retracting it falls under the Spring force.
Answer:
A quasar is an extremely bright, distant object visible to radio telescopes.
Answer:
It is constructed with a high mass and a high raidus.
Explanation:
The rotational inertia I for every object is calculated as:
cMR^2 = I
where c is a constant, M is the mass of the object and R the radius of the object.
So, for a flywheel, the rotational inertia is calculated as:
I =
Then, for constructed a flywheel with the maximun rotational inertia we have to set the maximum mass and the maximun radius.