Answer:
2 : 2
Explanation:
The balanced chemical equation is given as:
2K + Cl₂ → 2KCl
From the balanced reaction equation, we can conclude that;
- 2 moles of K will react with 1 mole of Cl₂
- 2 moles of K will produce 2 moles of KCl
- 1 mole of Cl₂ will produce 2 moles of KCl
Therefore, the mole ratio is 2:2 or 1:1 in the simplest form.
Answer: See below
Explanation:
n of CO2 = 0.364mmol
Mass of C = 0.364*12 = 4.368 mg
n of H2O = 184.37 = 0.243 mol
The compound has 2*0.243mmol of H
Mass of H = 0.486 mg
Mass of O = 10.68 − (4.368+0.486) = 5.826mg
Moles of O = 0.364
<u>C:H:O Ratios</u>
0.364 : 0.486 : 0.364
= 1 : 1.34 : 1
= 3 : 4 : 3
<u>So the empirical formula is C3H4O3,</u>
Empirical formula mass
= 88= 2 × Molar mass
<u>And the molecular formula is C6H8O6</u>
A compound with the formula C6H12 is not considered a Saturated hydrocarbon.
Why is C6H12 isn't considered a Saturated hydrocarbon?
The ring's presence demonstrates that it is unsaturated. Keep in mind that the general formula for aliphatic hydrocarbons, CnH2n+2, serves as the foundation for its saturation. A chemical is unsaturated if it does not meet this requirement.
Example:
Hexane (C6H14)
C = 6; H = 14 = 2(6) + 2
resulting in hexane becoming saturated.
Cyclohexane(C6H12)
C = 6 and H = 12 do not equal 14 (x)!
cyclohexane is an unsaturated molecule as a result.
Cycloalkanes have the general formula C2H2n as well.
Hence, the given statement is false.
Learn more about the hydrocarbons here,
brainly.com/question/17578846
# SPJ4
Answer:
C12H22O11(aq) + H2O(l) —> 4C2H5OH(aq) + 4CO2(g)
Explanation:
When aqueous sugar (sucrose) react with water in the presence of yeast, the following products are obtained as shown in the equation below:
C12H22O11(aq) + H2O(l) —> C2H5OH(aq) + CO2(g)
Now, we shall balance the equation as follow:
There are a total of 24 atoms of H on the left side and 6 atoms on the right side. It can be balance by putting 4 in front of C2H5OH as shown below:
C12H22O11(aq) + H2O(l) —> 4C2H5OH(aq) + CO2(g)
There are a total of 9 atoms of C on the right side and 12 atoms on the left side. It can be balance by putting 4 in front of CO2 as shown below:
C12H22O11(aq) + H2O(l) —> 4C2H5OH(aq) + 4CO2(g)
Now the equation is balanced.
The element has 83 electrons
