Answer:
C
Step-by-step explanation:
It is a function because it passes the vertical line test and Xs do not repeat, then count out the Y-values which are the range.
Answer:
1
Step-by-step explanation:
h
We assume the lunch prices we observe are drawn from a normal distribution with true mean and standard deviation 0.68 in dollars.
We average samples to get .
The standard deviation of the average (an experiment where we collect 45 samples and average them) is the square root of n times smaller than than the standard deviation of the individual samples. We'll write
Our goal is to come up with a confidence interval (a,b) that we can be 90% sure contains .
Our interval takes the form of as is our best guess at the middle of the interval. We have to find the z that gives us 90% of the area of the bell in the "middle".
Since we're given the standard deviation of the true distribution we don't need a t distribution or anything like that. n=45 is big enough (more than 30 or so) that we can substitute the normal distribution for the t distribution anyway.
Usually the questioner is nice enough to ask for a 95% confidence interval, which by the 68-95-99.7 rule is plus or minus two sigma. Here it's a bit less; we have to look it up.
With the right table or computer we find z that corresponds to a probability p=.90 the integral of the unit normal from -z to z. Unfortunately these tables come in various flavors and we have to convert the probability to suit. Sometimes that's a one sided probability from zero to z. That would be an area aka probability of 0.45 from 0 to z (the "body") or a probability of 0.05 from z to infinity (the "tail"). Often the table is the integral of the bell from -infinity to positive z, so we'd have to find p=0.95 in that table. We know that the answer would be z=2 if our original p had been 95% so we expect a number a bit less than 2, a smaller number of standard deviations to include a bit less of the probability.
We find z=1.65 in the typical table has p=.95 from -infinity to z. So our 90% confidence interval is
in other words a margin of error of
dollars
That's around plus or minus 17 cents.
Answer:
4.10
0.17
Step-by-step explanation:
From the question, we know that
A recent sociological report stated that university students drink 4.10 alcoholic drinks per week on average, with a standard deviation of 1.9101.
Also, we're tasked with finding the mean and standard deviation of the sampling distribution of the sample mean alcohol consumption.
To find the mean of the sampling distribution, we take the sample mean of the same of that university students as a direct substitute. This then means that the mean of the sampling distribution of the sample mean alcohol consumption is 4.10 alcoholic drinks per week on average.
On the other hand, the standard deviation of the sampling distribution of the sample mean alcohol consumption is taken to be the division of the standard deviation of the sample mean. Mathematically, we have
Standard Deviation, S = 1.9101 / √125
Standard Deviation, S = 1.9101 / 11.18
Standard Deviation, S = 0.17
Therefore, the Standard Deviation is 0.17
Convert to common denominator
3/4 = 12/16
Multiply by 16
(12/16)/(3/16)
12/3
Your answer is 4.
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