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Explanation:
like fr add me on snap
It releases Carbon Dioxide
Answer:
This a simple stoichiometry problem using the ideal gas law.
First take the grams of ammonium carbonate and convert it to moles using its molar mass and dividing. 11.9 g/96.0932 g/mol= .12384 mol
Now use a molar conversion using the balanced equation,
1 mol (NH4)2CO3 ---> 4 mol gas formed (2 mol NH3 + 1 mol CO2 + 1 mol H2O) = .12384 x 4 = .49535 mol gas
PV=nRT
V=nRT/P= .49535mol (.08206 Lxatm/molxK) (296K)/ (1.03 atm)=11.682 L
There is no gaseous product when NaNO3 reacts with 6M HCl.
We must note that gas evolution is one of the signs that a chemical reaction has taken place. Hence, we must consider the options and look out for an option in which reaction with HCl does not lead to a gaseous product. This is the option that does not lead to evolution of a gas.
Let us consider the reaction; NaNO3(s) + HCl(aq) ---> NaCl(s) + HNO3(aq), there is no gaseous product hence NaNO3 does not result in gas evolution upon addition of 6M HCl.
Missing parts;
Addition of 6 M HCl to which substance will NOT result in gas evolution?
(A) Al
(B) Zn
(C) K2CO3
(D) NaNO3
Learn more about evolution of gas: brainly.com/question/2186340
