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Gre4nikov [31]
3 years ago
14

- A beam of electrons has.....

Chemistry
1 answer:
adelina 88 [10]3 years ago
3 0

Answer:

(C) Both of these

Explanation:

A beam of electrons has both of these Wave properties and Particle properties.

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3. Which plane’s velocity was greatest?
Likurg_2 [28]

Answer:

North American X-15

Explanation:

This is the fastest manned aircraft

7 0
3 years ago
Read 2 more answers
In a particular experiment, 2.50-g samples of each reagent are reacted. The theoretical yield of lithium nitride is ________ g.
Neporo4naja [7]

Answer:

4.18 g

Explanation:

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Given: For Li

Given mass = 2.50 g

Molar mass of Li  = 6.94 g/mol

<u>Moles of Li  = 2.50 g / 6.94 g/mol = 0.3602 moles</u>

Given: For N_2

Given mass = 2.50 g

Molar mass of N_2 = 28.02 g/mol

<u>Moles of N_2 = 2.50 g / 28.02 g/mol = 0.08924 moles</u>

According to the given reaction:

6Li+N_2\rightarrow 2Li_3N

6 moles of Li react with 1 mole of N_2

1 mole of Li react with 1/6 mole of N_2

0.3602 mole of Li react with \frac {1}{6}\times 0.3602 mole of N_2

Moles of N_2 that will react = 0.06 moles

Available moles of N_2 = 0.08924 moles

N_2 is in large excess. (0.08924 > 0.06)

Limiting reagent is the one which is present in small amount. Thus,

Li is limiting reagent.

The formation of the product is governed by the limiting reagent. So,

6 moles of Li gives 2 mole of Li_3N

1 mole of Li gives 2/6 mole of Li_3N

0.3602 mole of Li react with \frac {2}{6}\times 0.3602 mole of Li_3N

Moles of Li_3N = 0.12

Molar mass of Li_3N = 34.83 g/mol

Mass of Li_3N = Moles × Molar mass = 0.12 × 34.83 g = 4.18 g

<u>Theoretical yield = 4.18 g</u>

5 0
3 years ago
This formula equation is unbalanced.
viktelen [127]

answer is: coefficient is 2.



8 0
3 years ago
Calculate the ratio of naf to hf required to create a buffer with ph = 4.05.
NARA [144]
PH is the test of acidity or basicity of a solution. it follows the formula: 
pH = pKa + log [salt] / [acid] where NaF is the salt and HF is the acid in this case. 

By literature, Ka of HF is 3.5*10^-4 
<span>pKa= -log(Ka)=</span><span> 3.46 </span>

<span>pH = pKa + log [NaF / [HF] </span>

4.05 = 3.46 + log [NaF / [HF] 

log [NaF / [HF]<span> = 0.59
</span>
[NaF / [HF] = 3.89
4 0
3 years ago
Read 2 more answers
Calculate the number of moles in 8 g of water.
polet [3.4K]

Answer:

refer the above attachment

4 0
1 year ago
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