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attashe74 [19]
3 years ago
10

The double bond between a carbon atom and two oxygen atoms (a molecule of carbon dioxide) has two characteristics. what are they

?
Chemistry
2 answers:
Ad libitum [116K]3 years ago
8 0
Carbon has four valence electrons. These electrons are associated for a specific atom and is responsible for forming a bond to different atoms. For carbon, in order to agree with the octet rule, it should have 4 more electrons. For an oxygen atom, there are 6 valence electrons present so it would need two more electrons. Thus, carbon atoms would share electrons with another two oxygen atoms wherein each oxygen atom would form double bonds with the carbon atom. So, the characteristics of these bonds would be that all of the four valence electrons of the carbon are being shared. 
Alexandra [31]3 years ago
6 0

Answer:

Valence electrons are shared between oxygen atoms AND

Four valence electrons are shared

Explanation:

Apex

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True I'm pretty sure
6 0
3 years ago
What is the oxidation state for a Mn atom?<br> (1) 0 (2) +7 (3) +3 (4) +4
ss7ja [257]

Answer : The correct option is, (1) 0

Explanation :

Oxidation state or oxidation number : It represent the number of electrons lost or gained by the atoms of an element in a compound.

Oxidation numbers are generally written with sign (+ and -) first and then the magnitude.

When the atoms are present in their elemental state then the oxidation number will be zero.

As per question, 'Mn' atom is a free element that means it is present in their elemental state then the oxidation state will be zero.

Hence, the correct option is, (1) 0

5 0
4 years ago
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Dahasolnce [82]

Answer:

second answer

Explanation:

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So it is answer 2

5 0
3 years ago
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Dmitri Mendeleev’s periodic law states that the chemical and physical properties repeat themselves in groups of
Evgen [1.6K]
B, it’s in groups of 8
4 0
4 years ago
Write the empirical formula of at least four binary ionic compounds that could be formed from the following ions: Zn2+, Ni4+, F-
hram777 [196]

Ionic compounds are formed between oppositely charged ions.

A binary ionic compound is composed of ions of two different elements - one of which is a positive ion(metal), and the other is negative ion (nonmetal).

To write the empirical formula of binary ionic compound we must remember that one ion should be positive and other ion should be negative, then only the correct formula should be written. To write the empirical formula the charges of opposite ions should be criss-crossed.

First empirical formula of binary ionic compound is written betweenZn^{2+} (Positive ion)and F^{-} (Negative ion)

First Formula would be ZnF_{2}

Second empirical formula is between Zn^{2+}(Positive ion) and O^{2-}(Negative ion)

Second Formula would be Zn_{2}O_{2}

Note : When the subscript are same they get cancel out, so Zn_{2}O_{2} would be written as ZnO

Third empirical formula is between Ni^{4+}(Positive ion) and F^{-}(Negative ion)

Third Formula would be :NiF_{4}

Forth empirical formula is between Ni^{4+}(Positive ion)and O^{2-}(negative ion)

Forth Formula would be : Ni_{2}O_{4} or NiO_{2}

Note- The subscript will be simplified and the formula will be written as NiO_{2}.

The empirical formula of four binary ionic compounds are : ZnF_{2}, ZnO, NiF_{4},NiO_{2}


8 0
3 years ago
Read 2 more answers
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