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qaws [65]
3 years ago
7

A jet airplane reaches 750 km/h on a certain flight. What distance does it cover in 10 min?

Chemistry
2 answers:
malfutka [58]3 years ago
3 0

The distance that jet covered in 10 min is 125 Km

calculation

distance = speed  x time

speed=750 km/h

time= 10/60hrs

=750 x10/60=125 Km

telo118 [61]3 years ago
3 0

Answer : The distance covered by jet airplane is 125.25 km

Explanation :

Speed : It is defined as the distance traveled by the object per unit time.

Formula used :

Speed=\frac{Distance}{Time}

Given:

Speed of jet airplane = 750 km/hr

Time = 10 min = 0.167 hr

conversion used : (1 hr = 60 min)

Now we have to determine the distance covered by jet airplane.

750km/hr=\frac{Distance}{0.167hr}

Distance=125.25km

Therefore, the distance covered by jet airplane is 125.25 km

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4 years ago
The first four planets in our solar system are rocky. How does that relate to Newton’s law of universal gravitation?
Serhud [2]

Explanation:

According to Newton law of gravity, the strength of gravitational pull between two objects is related to their masses, directly, and inversely by the distance between them;

F = G * (M₂ – M₁) / d where;

F – the force of gravity

G – gravitational constant

M₂ – the mass of one object

M₁ – the mass of the other object

d – the distance between the two objects

The rocky planets have a higher mass than the gas planets hence will be strongly ‘feel’ the gravitational pull of the star in the solar system revolves about.  This is why rocky planets are closer to their star while gas planets are towards the outer edges.

Learn More:

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5 0
3 years ago
6. 100 ml of gaseous hydrocarbon consumes 300
mario62 [17]

Answer:

  • <u><em>a. C₂H₄</em></u>

Explanation:

At constant pressure and temperature, the mole ratio of the gases is equal to their volume ratio (a consequence of Avogadro's law).

Hence, the <em>complete combustion reaction</em> that has a ratio of 100 ml of gaseous hydrocarbon to 300 ml of oxygen, is that whose mole ratio is 1 mol hydrocarbon : 3 mol of oxygen.

Then, you must write the balanced chemical equations for the complete combustion of the four hydrocarbons in the list of choices, and conclude which has such mole ratio (1 mol hydrocarbon : 3 mol oxygen).

A complete combustion reaction of a hydrocarbon is the reaction with oxygen that produces CO₂ and H₂O, along with the release of heat and light.

<u>a. C₂H₄:</u>

  • C₂H₄ (g) + 3O₂ (g) → 2CO₂(g)  + 2H₂O (g)

Precisely, for this reaction the mole ratio is 1 mol C₂H₄: 2 mol O₂, hence, this is the right choice.

The following analysis just shows that the other options are not right.

<u>b. C₂H₂:</u>

  • 2C₂H₂ (g) + 5O₂ (g) → 4CO₂(g)  + 2H₂O (g)

The mole ratio for this reaction is 2 mol C₂H₂ :5 mol O₂.

<u>с. С₃Н₈</u>

  • C₃H₈ (g) + 5O₂ (g) → 3CO₂(g)  + 4H₂O (g)

The mole ratio is 1 mol C₃H₈ : 5 mol O₂

<u>d. C₂H₆</u>

  • 2C₂H₆ (g) +7 O₂ (g) → 4CO₂(g)  + 6H₂O (g)

The mole ratio is 2 mol C₂H₆ : 7 mol O₂

7 0
4 years ago
Match each weather phenomena listed below to its appropriate scale of motion. longwave ridges and troughs microscale a high pres
Ipatiy [6.2K]

Answer:

Longwave ridges = Global scale

High pressure system persists over the central plains for 4 days = Synoptic scale

Supercell thunderstorm that lasts for over an hour = mesoscale

A turbulent eddy = microscale

Explanation:

Global scale has a range of the entire earth

synoptic scale has a range of about 100-1000km and can last fro days to weeks

mesoscale has a range of 4-100km and lasts for a day maximum

microscale is the least of all atmospheric motions.

6 0
3 years ago
17. What is the symbol for the element that forms a.
stepladder [879]
The answer is (C) Al
8 0
3 years ago
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