Answer:
0.6710
Step-by-step explanation:
The diameters of ball bearings are distributed normally. The mean diameter is 107 millimeters and the population standard deviation is 5 millimeters.
Find the probability that the diameter of a selected bearing is between 104 and 115 millimeters. Round your answer to four decimal places.
We solve using z score formula
z = (x-μ)/σ, where
x is the raw score
μ is the population mean = 107 mm
σ is the population standard deviation = 5 mm
For x = 104 mm
z = 104 - 107/5
z = -0.6
Probability value from Z-Table:
P(x = 104) = 0.27425
For x = 115 mm
z = 115 - 107/5
z = 1.6
Probability value from Z-Table:
P(x = 115) = 0.9452
The probability that the diameter of a selected bearing is between 104 and 115 millimeters is calculated as:
P(x = 115) - P(x = 104)
0.9452 - 0.27425
= 0.67095
Approximately = 0.6710
Answer:
Step-by-step explanation:
<u>Lets verify with Pythagorean:</u>
- 17² = 289
- 13² + 14² = 169 + 196 = 365
- 289 < 365
The angle opposite to a greater side is less than 90° and the sum of the squares are close.
It means all three angles<u> are less than 90°</u>.
With this the triangle is <u>acute</u>.
Correct choice is A.
Answer:
x = 4
Step-by-step explanation:
Since JB is the bisector of AD and the length of AD is given as 24 we can conclude that AZ is 12 (half of AD)
2x + 4 = 12
2x = 8
x = 4
2.5 rounds up to 3. Because the digit after the decimal point is 5 or more.
