Answer:
Glucose is a primary source of energy for living organisms. Animals transport glucose and oxygen to tiny structures in their cells, called mitochondria.
Hope this helps ;-))
Answer: -
3.3° C
Explanation: -
Mass of water m = 180.5 g
Energy released as heat Q = 2494 J
Specific heat is defined as the heat required to raise the temperature of the unit mass of a given substance by 1 C.
Specific heat of water Cp = 4.184 (J/g)⋅∘C
Using the formula
Q = m x Cp x ΔT
We get temperature change ΔT = Q / (m x Cp)
= 2494 J / ( 180.5 g x 4.184 (J/g)⋅∘C
= 3.3° C
Thus the temprature change, (ΔT), of the wateris 3.3 °C if 180.5 g of water sat in the copper pipe from part A, releasing 2494 J of energy to the pipe
Data:
m = 7 g
ΔT = 19 °C
Cs of water = 1 cal / g °C
Formula Q = m * Cs * ΔT
Solution:
Q = (7 g) * (1 cal / g °C) * ( 19°C) = 133 cal
