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expeople1 [14]
3 years ago
15

When each of the following processes reach equilibrium, does the system in question contain mostly reactants, mostly products, o

r fairly equal concentrations of both reactants and products? Justify your answers.
a. 2 H2(g) +02(g)2 H20(g)
b. H2(g + Br2(g)2HBr(g) K. 91 x 1080 at 25°C K-114 x 1021 at 25°C
Chemistry
1 answer:
jasenka [17]3 years ago
7 0

Answer:

Mostly products

Explanation:

Given the very large equilibrium constants for the two reactions we can consider them to be essentially 100 % complete to the product side.

The equilibrium constant for the reactions are given by:

a. K = p H₂O ² / (p H₂ ² x  p O₂ ) where p are the pressures  K = 91 x 10⁸⁰

b. K = p HBr ² / ( p H₂ x p Br₂ )   K = 114 x 10²¹

These two number are so big that  essentially very, very little amount of reactants are present after reaction.

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It is a subscript

Also do you mean Cl not Ci. I assume you do because then it means 4 chlorine in that compound.

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What mass of compound must be weighed out to have a 0.0223 mol sample of H2C2O4 (M=90.04 g/mol)?
rodikova [14]
Mass of  H2C2O4 :

mm = 90.04 g/mol

number of moles : 0.0223 moles

m = n * mm

m = 0.0223 * 90.04

m = 2.007 g 

hope this helps!.

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8 0
3 years ago
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Find the final equilibrium temperature when 15.0 g of milk at 13.0 degrees c is added to 148 g of coffee with a temperature of 8
user100 [1]

According to zeroth law of thermodynamics, when two objects are kept in contact, heat (energy) is transferred from one to the other until they reach the same temperature (are in thermal equilibrium). When the objects are at the same temperature there is no heat transfer.

So, at equilibrium, q_{lost}=q_{gain},  q_{lost}= q_{milk} + q_{coffee}

q=m×c×T, where q = heat energy, m = mass of a substance, c = specific heat (units J/kg∙K), T is temperature

q_{lost}= (15X13X4.19)+(148X88.3X4.19), (15+148)X4.19XT_{final}=(15X13X4.19)+(148X88.3X4.19)

T_{final}= 81.37 ° C

6 0
3 years ago
A gas is at a pressure of 4.30 atm. what is this pressure in kilopascals? in mm hg?
Monica [59]
Units to measure pressure are as follows
atm - atmospheric pressure units
kPa - kilo Pascals
mm Hg - milimeters Hg
conversion units are;
 1 atm = 101 325 Pa
therefore 4.30 atm = 101 325 Pa / atm x 4.30 atm = 435.7 Pa

1 atm = 760.0 mm Hg
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answers are 435.7 Pa and 3268 mm Hg
5 0
3 years ago
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