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expeople1 [14]
4 years ago
15

When each of the following processes reach equilibrium, does the system in question contain mostly reactants, mostly products, o

r fairly equal concentrations of both reactants and products? Justify your answers.
a. 2 H2(g) +02(g)2 H20(g)
b. H2(g + Br2(g)2HBr(g) K. 91 x 1080 at 25°C K-114 x 1021 at 25°C
Chemistry
1 answer:
jasenka [17]4 years ago
7 0

Answer:

Mostly products

Explanation:

Given the very large equilibrium constants for the two reactions we can consider them to be essentially 100 % complete to the product side.

The equilibrium constant for the reactions are given by:

a. K = p H₂O ² / (p H₂ ² x  p O₂ ) where p are the pressures  K = 91 x 10⁸⁰

b. K = p HBr ² / ( p H₂ x p Br₂ )   K = 114 x 10²¹

These two number are so big that  essentially very, very little amount of reactants are present after reaction.

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A chemistry student needs 15.0 g of methanol for an experiment. She has available 320. g of 44.4% w/w solution of methanol in wa
Makovka662 [10]

Answer:

33.8 g Solution

Explanation:

A chemistry student needs 15.0 g of methanol for an experiment. The concentration of ethanol in the solution is 44.4% w/w, that is, there are 44.4 g of methanol every 100 g of solution. The mass of solution that would contain 15.0 g of methanol is:

15.0 g Methanol × 100 g Solution/44.4 g Methanol = 33.8 g Solution

Since 33.8 g are required and 320. g are available, there is enough solution for the requirements.

4 0
3 years ago
Infer if the mineral Talc would be a good choice when building a statue outside?
ruslelena [56]
Talc is not a good choice when building a statue because the mineral Talc is one of the weakest minerals on the Mohs Scale with a hardness of 1 since it could be scratched by a fingernail, which means that when people build a statue with Talc, it could be easily broken down.
5 0
3 years ago
Potassium chlorate is a mean little chemical. It likes to decompose rather violently, and when it does, it decomposes into two d
WARRIOR [948]

Answer:

Oxygen gas

Explanation:

Potassium chlorate KClO3 decomposes thermally to form potassium chloride KCl and oxygen gas is given off. This is in the presence of a catalyst, manganese iv oxide.

Hence, what is being said in essence is that when potassium chloride is heated in the presence of manganese iv oxide catalyst, oxygen is given off as the gaseous product with the formation of potassium chloride.

The chemical equation for the reaction is :

2KClO3 ——-> 2KCl + 3O2

This procedure is one of most important ways through which oxygen can be produced in the laboratory and can be used as a source of oxygen is industrial processes if on a large scale

6 0
3 years ago
Calculate the solubility at 25°c of cubr in pure water and in a 0.0030m cobr2 solution. you'll find ksp data in the aleks data t
Reil [10]

Answer:

the solubility at 25°c of cubr in pure water = 0.011 g/L

The solubility at 25°c of cubr  in a 0.0030m cobr2 solution = 0.00014 g/L

Explanation:

Step 1: Data given

Ksp of CuBr = 6.27 × 10^-9

Molar mass CuBr = 143.45 g/mol

Step 2: Calculate the solubility at 25°c of cubr in pure water

Ksp = [Cu+][Br-]

The initial concentration

[Cu+] = 0M

[Br-] = 0M

The concentration at the equilibrium

[Cu+] = X M

[Br-] = X M

Ksp =6.27 * 10^-9 =  X * X = X²

S = 7.9 *10^-5 mol /l  

7.9 * 10^-5 mol/L * 143.45 g/mol = 0.011 g/L

Step 3: Calculate the solubility at 25°c of cubr  in a 0.0030m cobr2 solution.

The balanced equation:

CoBr2(aq) → Co^2+(aq) + 2 Br⁻(aq)

For 1 mol CoBr2 we'll have 1 mol Co^2+ and 2 moles Br-

For 0.0030 M CoBr2 we'll have 0.0030 M Co^2+ and 0.0060 M Br-

The initial concentration

[Cu+] = 0M

[Br-] = 0.0060 M

At the equilibrium

[Cu+] = X

[Br-] = 0.0060 + X

Ksp = 6.27 * 10^-9 = X * (0.0060+X)

6.27 *10^-9 = 0.0060 X + X²

X = 1.0 * 10^-6 mol/L

1.0 * 10^-6 mol/L * 143.45 g/mol = 0.00014 g/L

6 0
3 years ago
How are humans activity contributing to climate change?
ad-work [718]

Answer:

Some human activities that contribute to climate change would be fracking, driving vehicles, deforestation, and developing cities. Fracking releases methane and other greenhouses gases into the atmosphere. Driving vehicles, like cars or trains, also releases carbon dioxide into the atmosphere. Deforestation decreases the amount of oxygen being produced. Developing cities also contributes because it consumes almost 80% of the world's energy, as well as producing 60% of the greenhouse gases.

4 0
3 years ago
Read 2 more answers
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