Question

The slope of the line formed from ln(k) vs 1/T represents which of the following? A. Ea B. Ea/R C. -Ea D. -Ea/R

Answer 1

Answer:

C

Explanation:

cause it looks right and I also studied but wait til someone gives another answer

Answer 2

The slope of the line formed from ln(k) vs 1/T represents $-\left(\frac{E_{a}}{R}\right)$

Answer: Option D

Explanation:

Based on the Arrhenius equation, we can calculate the activation energies if rate constant is well-known, or vice versa. It also expresses mathematically the relationship: as the activation energy component $E_{a}$ increases, the rate constant k decreases, so the reaction rate decreases.

The Arrhenius equation is $k=A e^{-E a / R T}$

Taking logarithm on both the sides we will have $\ln k=-\frac{E_{a}}{R T}+\ln A$

We know the equation y=mx+c where ‘ m ‘ is the slope and c is the Intercept

Equating y=mx+c to the logarithmic equation

we have y= ln k  

$m=-\frac{E_{a}}{R}$

x=1/T and  

c =ln A

so, slope $m=\frac{-E_{a}}{R}$ that  is the answer