3 years ago

Ava bought a rectangular rug for her hallway. The rug is 23 yards wide and 234 yards long.

Mathematics

1 answer:

Nookie1986 [14]3 years ago

4 0

Answer:

1 5/6

Step-by-step explanation:

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Write the first five terms of the geometric sequence in which a1=8 and the common ratio is -1/2.

Oliga [24]

Answer:

First five terms are:

8 , (-4) , 2 , (-1) , (1/2)

Step-by-step explanation:

$a_{1}=8 \\\\r = \frac{-1}{2}\\\\a_{2}=\frac{-1}{2}*a_{1}= \frac{-1}{2}*8= -4\\\\a_{3}=\frac{-1}{2}*a_{2}=\frac{-1}{2}*-4=2\\\\a_{4}=\frac{-1}{2}*a_{3}=\frac{-1}{2}*2=-1\\\\a_{5}=\frac{-1}{2}*a_{4}=\frac{-1}{2}*-1=\frac{1}{2}$

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3 years ago

Please Help.(picture below) 30 points

Sveta_85 [38]

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3 years ago

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(8d+4)–(d+2)<br><br> Subtract

icang [17]

Answer:

7d+2

Step-by-step explanation:

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2 years ago

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Please help with this I am completely stuck on it

vaieri [72.5K]

Answer:

$f(x)=\sqrt[3]{x-4} , g(x)=6x^{2}\textrm{ or }f(x)=\sqrt[3]{x},g(x)=6x^{2} -4$

Step-by-step explanation:

Given:

The function, $H(x)=\sqrt[3]{6x^{2}-4}$

Solution 1:

Let $f(x)=\sqrt[3]{x}$

If $f(g(x))=H(x)=\sqrt[3]{6x^{2}-4}$ , then,

$\sqrt[3]{g(x)} =\sqrt[3]{6x^{2}-4}\\g(x)=6x^{2}-4$

Solution 2:

Let $f(x)=\sqrt[3]{x-4}$ . Then,

$f(g(x))=H(x)=\sqrt[3]{6x^{2}-4}\\\sqrt[3]{g(x)-4}=\sqrt[3]{6x^{2}-4} \\g(x)-4=6x^{2}-4\\g(x)=6x^{2}$

Similarly, there can be many solutions.

7 0

3 years ago

Multiply: (x – 4)(x + 5)

denpristay [2]

Answer:

D. x2 + x - 20.

Step-by-step explanation:

(x – 4)(x + 5).

= x(x + 5) -4(x + 5).

= x2 + 5x – 4x – 20.

= x2 + x - 20.

3 0

3 years ago