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LuckyWell [14K]
2 years ago
6

Mr. MacDougall got his vehicle stuck in the snow. Being the nice student that you are, you stop to help Mr. MacDougall out of th

e snow. You exert a force of 350N on his vehicle and manage to push it 15m and completely out of the snow. How much work was done on the vehicle?
Physics
1 answer:
zhannawk [14.2K]2 years ago
4 0

Answer:

Explanation:

work done=force*displacement

=350N*15m

=5250 joule

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Looking for some help with the left side of the table and the questions followed :)
Inessa [10]

Answer:

(1). Going in the order: Gas, Liquid, Solid.

    Particle separation: Very large; large; small.

    Strength of forces between particles: very weak; weak; strong.

(2). a. The change of state is condensation.

     b. The density of the substance is increasing as particles move closer together.  

(3). a. The liquid's temperature decreases until it reaches solidification (freezing) point, and then the temperature will remain constant until all of the liquid has solidified.

     b. The particles move with less and less energy until they have low enough energy to come together and solidify, then they will release more energy when they come together to form bonds, and vibrate about their equilibrium positions once they are part of a  molecular bond.

Additional explanation:

(1). The particle separation in a gas is very large because the gas has a very low density, and since particles are not that close together,<em> the strength of forces between particles is very weak</em>.

The liquid is somewhat more denser than the gas and therefore the particle separation is large but less than that in a gas,<em> The strength of forces between particles is still weak but greater  than in a gas. </em>

Finally, particle separation in a solid is small because the solid is still more denser than the liquid, and the strength of forces between particles is strong because it's these forces that give a solid its rigid shape.

(2). a.The change of state of a substance in which particles slow down and move close together is called condensation.

    b. As the particles move close together, they are occupying less and less volume; therefore, the density is increasing.

(3). The explanation is already given in the answer.

6 0
3 years ago
In Figure 10-1, if the force exerted on a 3.0-kg backpack that is initally at rest is 20.0 N and the distance it acts over is 0.
pshichka [43]
I'm going to assume this is over a horizontal distance. You know from Newton's Laws that F=ma --> a = F/m. You also know from your equations of linear motion that v^2=v0^2+2ad. Combining these two equations gives you v^2=v0^2+2(F/m)d. We can plug in the given values to get v^2=0^2+2(20/3)0.25. Solving for v we get v=1.82 m/s!
4 0
3 years ago
Can you hear it? In the cartoon space rocket, why do you think you would not be able to hear the whoosh of the rocket engine in
Brums [2.3K]

Answer:

Because space is a void with no air flow

Explanation:

7 0
2 years ago
Mechanical energy is conserved in the presence of which of the following types of forces?magnetic
Tju [1.3M]
<h2>Answer: electrostatic and gravitational force </h2><h2 />

Mechanical energy remains constant (conserved) if only <u>conservative forces</u> act on the particles.  

In this sense, the following forces are conservative:  

-Gravitational  

-Elastic

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While the Friction Force and the Magnetic Force are not conservative.

According to this, mechanical energy is conserved in the presence of electrostatic and gravitational forces.

7 0
3 years ago
41. Planet Ayanna has a radius of 6.2 X 10%m and orbits the star named Dayli in 98 days. A new neighboring planet Clayton J-21 h
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Answer:

138.3 days

Explanation:

Given that a Planet Ayanna has a radius of 6.2 X 10%m and orbits the star named Dayli in 98 days. A new neighboring planet Clayton J-21 has been discovered and has a radius of 7.8 X 10 meters.

The period of time for Clayton J-21 to orbit Dayli can be calculated by using Kepler law.

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That is,

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Make T^2 the subject of formula.

T^2 = 98^2 / 62^3 × 78^3

T^2 = 19123.2

T = sqrt ( 19123.2 )

T = 138.2867 days

Therefore, the period of time for Clayton J-21 to orbit Dayli is 138.3 days approximately.

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2 years ago
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