Answer:
The spring constant = 9.25 N/m
Explanation:
The equation of an object attached to a spring that is oscillating is
T = 2π√(m/k)
Where T = period of the oscillation, m = mass of the object, k = spring constant.
Making k the subject of the equation,
k = 4π²m/T²......................... Equation 1
Note: Period(T) is the time taken to complete one oscillation
Given: T = t/10 = 9.0/10 = 0.9 s, m = 190 g = 0.19 kg.
Constant: π = 3.14
Substitute these values into equation 1.
k = 4(3.14)²(0.19)/0.9²
k = 7.4933/0.81
k = 9.25 N/m
Thus the spring constant = 9.25 N/m
Answer:
or 0.07163 T into the page
Explanation:
m = Mass of particle = 10 g
a = Acceleration due to gravity = -9.8j m/s²
v = Velocity of particle = 19i km/s
q = Charge of particle = 72 μC
B = Magnetic field
Here the magnetic and gravitational forces on the particle are applied in the opposite direction so,
The magnetic field is 0.07163 T into the page
Answer:
the one that has more negative sights so the first hand on your right :)
