4/3 m/s ( approximately 1.3333... m/s)
Answer:
<em>at</em><em> </em><em>rest</em><em> </em><em>and</em><em> </em><em>in</em><em> </em><em>motion</em>
Explanation:
<em>The</em><em> </em><em>law</em><em> </em><em>of</em><em> </em><em>inertia</em><em> </em><em>applies</em><em> </em><em>to</em><em> </em><em>objects</em><em> </em><em>at</em><em> </em><em>rest</em><em> </em><em>and</em><em> </em><em>in</em><em> </em><em>motion</em>
Answer:
Sagittarius
Explanation:
The center of the Milky Way galaxy lies in the direction of the Sagittarius constellation, about 26,000 light-years away.
Answer:
There is an interval of 24.28s in which the rocket is above the ground.
Explanation:





From Kinematics, the position
as a function of time when the engine still works will be:

At what time the altitud will be
?
⇒ 
Using the quadratic formula:
.
How much time does it take for the rocket to touch the ground? No the function of position is:

Where our new initial position is
, the velocity when the engine breaks is
and the only acceleration comes from gravity (which points down).
Now, when the rocket tounches the ground:
Again, using the quadratic ecuation:

Now, the total time from the moment it takes off and the moment it tounches the ground will be:
.