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2 years ago

HELP!!

Physics

2 answers:

raketka [301]2 years ago

5 0

Hello!

Since the two weights are <em>off</em> the table, the block will move towards letter F.

I hope this helps :))

Temka [501]2 years ago

5 0

If you wanted the block to remain in the center of the table what masses of blocks would you add and where? Use the letters going around the table to identify their locations and tell me the mass you would make the block at that location (for example Point B 6000g)

Now explain your reasoning:

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A train travels 2km in 100 seconds. find the velocity of the train

AVprozaik [17]

Answer:

20m/s = 72km/h

Explanation:

change 2km=2000m

The speed of the train is

v.t=S <=> v=S/t=2000/100=20 m/s

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2 years ago

(a) Calculate how much work is required to launch a spacecraft of mass m from the surface of the earth (mass mE, radius RE) and

notsponge [240]

Answer:

(a) The Work need to place spacecraft into low orbit is $Gmm_{E} /2R_{E}$

(b) Additional Work need to place the spacecraft far away from the earth is

$Gmm_{E} /2R_{E}$ .

Explanation:

Explanation is in the following attachments

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2 years ago

What cause sound? And how do it work

tatuchka [14]

Answer:

Simple yet quick mechanical vibrations of various elastic substances produce sound. When they are moved or struck to vibrate, the auditory nerve of the ear receives the same sort of vibrations, which are subsequently perceived by the mind.

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2 years ago

a golfer tees off and hits a golf ball at a speed of 31 m/s and an angle of 35 degrees. how far did the ball travel before hitti

poizon [28]

Ans: R = Ball Travelled = 92.15 meters.

Explanation:
First we need to derive that formula for the "range" in order to know how far the ball traveled before hitting the ground.

Along x-axis, equation would be:
$x = x_o + v_o_xt + \frac{at^2}{2}$

Since there is no acceleration along x-direction; therefore,
$x = x_o + v_o_xt$

Since $v_o_x = v_ocos \alpha$ and $x_o$ =0; therefore above equation becomes,

$x = v_ocos \alpha t$ --- (A)

Now we need to find "t", and the time is not given. In order to do so, we shall use the y-direction motion equation. Before hitting the ground y ≈ 0 and a = -g; therefore,

=> $y = y_o + v_o_yt - \frac{gt^2}{2}$
=> $t = \frac{2v_o_y}{g}$

Since $v_o_y = sin \alpha$ ; therefore above equation becomes,
$t = \frac{2v_osin \alpha }{g}$

Put the value of t in equation (A):

(A) => $x = v_ocos \alpha \frac{2v_osin \alpha }{g}$

Where x = Range = R, and $2sin \alpha cos \alpha = sin(2 \alpha )$ ; therefore above equation becomes:

=> $R = (v_o)^2 *\frac{sin(2 \alpha )}{g}$

Now, as:
$v_o = 31 m/s$

and $\alpha = 35$ °
and g = 9.8 m/(s^2)

Hence,
$R = (31)^2 *\frac{sin(2 *35 )}{9.8}$

Ans: R = 92.15 meters.

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2 years ago

At NASA's Zero Gravity Research Facility in Cleveland, Ohio, experimental payloads fall freely from rest in an evacuated vertica

Diano4ka-milaya [45]

Answer:

(a). Energy is 64,680 J

(b) velocity is 51.43m/s

Explanation:

(a).

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