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Tomtit [17]
3 years ago
14

HELP!!

Physics
2 answers:
raketka [301]3 years ago
5 0
Hello!

Since the two weights are <em>off</em> the table, the block will move towards letter F. 

I hope this helps :))
Temka [501]3 years ago
5 0

If you wanted the block to remain in the center of the table what masses of blocks would you add and where?  Use the letters going around the table to identify their locations and tell me the mass you would make the block at that location (for example  Point B 6000g)

Now explain your reasoning:

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Matter that emits no light at any wavelength is called
lorasvet [3.4K]

Matter that emits no light at any wavelength is called DARK MATTER.

4 0
3 years ago
A transverse wave is traveling through a canal. If the distance between two successive crests is 3.17 m and four crests of the w
Thepotemich [5.8K]

Answer:

a. 0.18Hz

b. 0.56m/s

Explanation:

From the question we can deduct the following parameters

The wavelength, λ is define as the distance between two successful crest or trough and from the question we conclude that wavelength is 3.17m.

Also the period of the wave T can be computed as

T=22.6/4

T=5.65secs.

a. To compute the frequency, recall that frequency, F=1/period.

Hence,

F=1/5.65

F=0.18Hz

b. Next we compute the wave speed.

Wave speed=frequency *wavelength

Wave speed =0.18*3.17

Wave speed =0.56m/s

5 0
3 years ago
Need help on this,<br>will mark brainliest if you answer.<br>​
Alecsey [184]

Answer:

(1) tropical storm

(2) Severe tropical storm

(3) 305 kmh

5 0
3 years ago
Through which of these media do sound waves travel most slowly? A.iron. B.Wood. C.Water. D.Cold Air
EleoNora [17]
The answer should be D) Cold air because even though its true sound can travel through all types of matter, air which is a gas, can travel but it travels SLOWLY while sound travels quickly in SOLIDS.
5 0
4 years ago
An electron is projected with an initial speed of 5 3.2 10 / ⋅ m s directly toward a proton that is fixed in place. If the elect
Dvinal [7]

Answer:

The distance is d =1.66*10^{-9}m

Explanation:

From the question we are told that

         The initial speed of the  electron is v_i  = 3.2 *10^5 m/s

         The mass of electron is m = 9.11*10^{-31}kg

         Let d be the distance between the electron and the proton when the speed of the electron instantaneously equal to twice the initial value

         Let KE_i be the initial kinetic energy of the electron \

          Let KE_d be the kinetic energy of the electron at the distance d from the proton

  Considering that energy is conserved,

  The energy at the initial position of the electron = The energy at the final position of the electron

      i.e

             KE_i +U_1 = KE_d + U_2

U_1 \ and \ U_2 are the potential energy at the initial  position of the electron and at distance d of the electron to the proton

                Here U_1 = 0

So the equation becomes

                   \frac{1}{2} mv_i^2 = \frac{1}{2} mv_d^2  + \frac{kq_1 q_2}{d}

Here q_1 \ and  \ q_2 are the charge on the electron and the proton and their are the same since a charge on an electron is equal to charge on a proton

 k is electrostatic constant with value 8.99*10^9 N \cdot m^2 /C^2

i.e q = 1.602 *10^{-19}C

           v_d is the velocity at distance d from the proton = 2v_i

  So the equation becomes

             \frac{1}{2}mv_i^2 = \frac{1}{2} m (2v_i)^2 -\frac{k(q)^2}{d}

            \frac{1}{2} mv_i^2  = 4 [\frac{1}{2}mv_i^2 ]- \frac{k(q)^2}{d}

           3[\frac{1}{2}mv_i^2 ] = \frac{k(q)^2}{d}

Making d the subject of the formula

           d = \frac{2k(q)^2}{3mv_i^2}

              = \frac{2* 8.99*10^9 *(1.602*10^{-19}^2)}{3 * 9.11*10^{-31} *(3.2*10^5)^2}

              =1.66*10^{-9}m

             

           

         

                 

   

6 0
3 years ago
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