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anygoal [31]
3 years ago
9

What is the frequency of radiation emitted by a photon of light if the energy released during its transition to ground state is

3.611 × 10-15 joules? (Planck's constant is 6.626 × 10-34 joule seconds) 5.50 × 10-11 Hz 2.39 × 10-50 Hz 5.45 × 1018 Hz 1.633 × 1027 Hz
Physics
1 answer:
miskamm [114]3 years ago
3 0
If i was feeling harsh today, I'd say the answer to your question is impossible to obtain due to the fact that photons do not emit radiation, photons ARE the radiation emitted. Though for the sake of it, here is the method...

<u>The simple method:
</u>

E=hf

therefore f=e/h

f=(3.611x10^-15) / 6.63x10^-34)

Answer: 5.45x10^18
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Setler79 [48]

Answer:

Series

Explanation:

Because I listen to my science teacher

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3 years ago
Light refracts when it passes through some objects. What is refraction?
blagie [28]

Answer:

Explanation:

in physics, the change in direction of a wave passing from one medium to another caused by its change in speed. For example, waves in deep water travel faster than in shallow.from one medium to another or from a gradual change in the medium. Refraction of light is the most commonly observed phenomenon, but other waves such as sound waves and water waves also experience refraction in other words it can be all of them or i can narrow it down some more it can have a change in dirction when light enters into a traveling point for example after moving through air it passes through a prism called  compare reflection

6 0
3 years ago
An object of mass m is dropped from a height h above the surface of a planet of mass M and radius R. Find the speed of the objec
Shtirlitz [24]

Answer:

v=\sqrt{\frac{2GMh}{R^{2}}}

Explanation:

mass of object = m

Mass of planet = M

Radius of planet = R

Height = h

Let the speed of the object as it hits the earth's surface is v.

the value of acceleration due to gravity

g = G M / R^2

where, g is the universal gravitational constant.

Use third equation of motion

v^{2}=u^{2}+2gh

where, u is the initial velocity which is equal to zero.

So, v^{2}=0 + 2 \times \frac{GM}{R^{2}}\times h

v=\sqrt{\frac{2GMh}{R^{2}}}

8 0
4 years ago
Some workers are trying to lift up to the third floor of a building, which is 8.0 meters above the ground. The piano is 500 kg w
irina1246 [14]

Answer:

Weight = 4900 N

Explanation:

Given:

Mass of the piano is, m=500\ kg

Acceleration due to gravity is, g=9.8\ m/s^2

Height to which the piano is raised is 8.0 m.

We are asked to determine the weight of the piano.

We know that, weight of a body is nothing but gravitational force acting on it by the center of Earth. It is equal to the product of mass and acceleration due to gravity.

Weight is independent of height til the height is very less than the radius of Earth. At very high altitudes which are comparable to the radius of Earth, the value of 'g' changes and hence the weight. But, here the height is very small and hence the value of 'g' equals 9.8 m/s² only.

Thus, weight of the piano is given as:

Weight = Mass \times Acceleration due to gravity

Weight = mg

Weight = (500\ kg)(9.8\ m/s^2)=4900\ N

Weight is a force so, its unit is same as that of force and hence it is measured in Newtons.

Therefore, the weight of the piano is 4900 N.

8 0
3 years ago
Learning Goal: To practice Problem-Solving Strategy 4.1 for projectile motion problems. A rock thrown with speed 12.0 m/s and la
lesantik [10]

Answer:

The height from which the rock was thrown is 1.92 m

Solution:

As per the question:

Speed with which the rock is thrown, v = 12.0 m/s

Horizontal distance traveled by the rock before it hits the ground, d = 15.5 m

Launch angle, \theta = 30.0^{\circ}

Now,

To calculate the height, h from which the rock was thrown:

First, since we consider the horizontal motion in the trajectory of the rock, thus the time taken is given by:

t = \frac{d}{vcos\theta}

t = \frac{15.5}{12.0cos30.0^{\circ}} = 1.49\ s

Now,

The height from which the rock was thrown is given by the kinematic eqn, acceleration in the horizontal direction is zero:

h = vsin\theta t - \frac{1}{2}gt^{2}

h = 12.0sin30.0^{\circ}\times 1.49 - \frac{1}{2}\times 9.8\times 1.49^{2} = - 1.92\ m

8 0
3 years ago
Read 2 more answers
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