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2 years ago

How do the amplitudes of a 120 decibel sound and a 100-decibel sound compare?

1 answer:

4 0

The 120 decibel sound has more amplitude than the 100 decibel sound.

In Physics, the relation between amplitude and intensity is that the intensity of the wave is directly proportional to the square of its amplitude.

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Which best describes how heat energy moves within a system?

Rzqust [24]

<span>Heat energy is transferred from warmer objects to cooler objects.

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3 years ago

Read 2 more answers

A bungee cord with a spring constant of 800 stretches 6 meters at its greatest displacement. How much elastic potential energy d

Vinil7 [7]

Elastic potential energy is given by formula

$U = \frac{1}{2} kx^2$

here we know that

$k = 800 N/m$

$x = 6 m$

Now using above formula we have

$U = \frac{1}{2}(800)(6^2)$

$U = 14400 J$

So elastic potential energy in the chord is 14400 J

4 0

3 years ago

Please help with this

frosja888 [35]

912.

outer ear:
pinna
ear canal

middle ear:
ossicles and ear drum

inner ear:
semcircular canals
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auditory nerve

13.
frequency = wavespeed ÷ wavelength

14.
if frequency increases you would experience a higher pitch in sound

15.
humans can hear 20Hz to 20kHz

16.
The Doppler effect is the change in frequency or wavelength of a wave for an observer who is moving relative to the wave source. Can be used for machines measuring speed via doppler effect.

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Doppler in hospitals can be used for ultrasound to provide images for diagnosis and monitoring.

8 0

3 years ago

The speed of sound in room temperature (20°C) air is 343 m/s; in room temperature helium, it is 1010 m/s. The fundamental freque

Lera25 [3.4K]

Answer: f = 927.55Hz

Explanation: Since the the tube is open-closed, the length of air and the wavelength of sound passing through the tube is given below

L = λ/4 where λ = wavelength.

speed of sound in air = v = 343m/s.

fundamental frequency of open closed tube = 315Hz

λ = 4L.

v = fλ

343 = 315 * 4L

343 = 1260 * L

L = 343/ 1260

L = 0.27m

In the same tube of length L = 0.27m but different medium ( helium), the speed of sound is 1010m/s.

The length of tube and wavelength are related by the formulae below

L = λ/4, λ=4L

λ = 4 * 0.27

λ = 1.087m.

v = fλ

1010 = f * 1.087

f = 1010/1.807

f = 927.55Hz

4 0

3 years ago

The tension in the rope is constant and equal to 40 N as the block is pulled. What is the instantaneous power (in W) supplied by

Eduardwww [97]

Complete Question:

A 10 kg block is pulled across a horizontal surface by a rope that is oriented at 60° relative to the horizontal surface.

The tension in the rope is constant and equal to 40 N as the block is pulled. What is the instantaneous power (in W) supplied by the tension in the rope if the block when the block is 5 m away from its starting point? The coefficient of kinetic friction between the block and the floor is 0.2 and you may assume that the block starting at rest.

Answer:

Power = 54.07 W

Explanation:

Mass of the block = 10 kg

Angle made with the horizontal, θ = 60°

Distance covered, d = 5 m

Tension in the rope, T = 40 N

Coefficient of kinetic friction, $\mu = 0.2$