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liq [111]
3 years ago
14

A runner moves 8 miles every 1 minute. Write and graph an equation in two variables that shows the relationship between time and

distance
Mathematics
1 answer:
Mila [183]3 years ago
5 0

Answer:

what grade is this?

Step-by-step explanation:

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Solve this questions​
Alchen [17]

Answer:

a) Sale Price; Rs. 800        Discount rate: 20%

b) Sale Price; Rs. 4000     Discount rate: 20%

c) Sale Price; Rs. 6000     Discount rate: 35%

Step-by-step explanation:

1. Approach

In these problems, one is given a list of original prices and the amount of price taken off during a discount. One has to find the sale price and the rate of discount. The easiest way to find the sale price is to subtract the discount price from the original price. The general train of thought to do this can be found in the following formula:

(original\ price)-(discount\ amount)=(sale\ price)

One is also asked to find the rate of discount. Use the following proportion format to do so:

\frac{discount\ amount}{original\ price}=\frac{percent}{100}

Substitute each of the values in the given problem into the equation and solve for the price.

2. Part A

Original price: 1000

Discount: 200

<u>1. Sale price</u>

  • Formula
  • (original\ price)-(discount\ amount)=(sale\ price)
  • Substitute and solve,
  • 1000-200=(sale\ price)
  • \\800 = sale\ price

<u>2. Discount rate</u>

  • Formula
  • \frac{discount\ amount}{original\ price}=\frac{percent}{100}
  • Substitute, simplify, and solve
  • \frac{200}{1000}=\frac{percent}{100}
  • \frac{1}{5}=\frac{percent}{100}
  • (5)(percent)=1(100)
  • percent=20

3. Part B

Original price: 5000

Discount: 1000

<u>1. Sale price</u>

  • Formula,
  • (original\ price)-(discount\ amount)=(sale\ price)
  • Substitute and solve
  • 5000-1000=(sale\ price)
  • 4000=(sale\ price)

<u>2. Discount rate</u>

  • Formula
  • \frac{discount\ amount}{original\ price}=\frac{percent}{100}
  • Substitute, simplify, and solve
  • \frac{1000}{5000}=\frac{percent}{100}
  • \frac{1}{5}=\frac{percent}{100}
  • 5(percent)=1(100)
  • percent=20

4. Part C

Original price: 8000

Discount: 2000

<u>1. Sale price</u>

  • Formula
  • (original\ price)-(discount\ amount)=(sale\ price)
  • Substitute and solve
  • 8000-2000=(sale\ price)
  • 6000=(sale\ price)

<u>2. Discount rate</u>

  • Formula,
  • \frac{discount}{amount}=\frac{percent}{100}
  • Substitute, simplify and solve,
  • \frac{2000}{8000}=\frac{percent}{100}
  • \frac{1}{4}=\frac{percent}{100}
  • 4(percent)=1(100)
  • percent=25
7 0
3 years ago
Can someone help me with this please ?
VARVARA [1.3K]

Answer:

x= 65

Step-by-step explanation:

x= 360- (130+75+90)

x= 360- 295

x= 65 degrees

6 0
3 years ago
Jackson is given the expression below to simplify.
shepuryov [24]

The Answer is

3(6x+5)

7 0
3 years ago
Read 2 more answers
If 50% of a number is 300, what is the numbers?​
kotegsom [21]

<em><u>5</u></em><em><u>0</u></em><em><u> </u></em><em><u>per</u></em><em><u> </u></em><em><u>cent</u></em><em><u> </u></em><em><u>can</u></em><em><u> </u></em><em><u>also</u></em><em><u> </u></em><em><u>be</u></em><em><u> </u></em><em><u>termed</u></em><em><u> </u></em><em><u>as</u></em><em><u> </u></em><em><u>a</u></em><em><u> </u></em><em><u>half</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>number</u></em><em><u>.</u></em>

<em><u>therefore</u></em><em><u> </u></em><em><u>3</u></em><em><u>0</u></em><em><u>0</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>a</u></em><em><u> </u></em><em><u>½</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>original</u></em><em><u> </u></em><em><u>number</u></em>

<em><u>3</u></em><em><u>0</u></em><em><u>0</u></em><em><u> </u></em><em><u>multiplied</u></em><em><u> </u></em><em><u>by</u></em><em><u> </u></em><em><u>2</u></em>

<em><u>answer</u></em><em><u>=</u></em><em><u> </u></em><em><u>6</u></em><em><u>0</u></em><em><u>0</u></em>

4 0
4 years ago
Suppose a brand of lightbulbs is normally distributed with a mean life of 1900 hours and a standard deviation of 50 hours. Find
Alexxandr [17]
I am not sure exactly how to do it but based on my knowledge, I think the answer would be 1/38
6 0
4 years ago
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