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2 years ago

14

A runner moves 8 miles every 1 minute. Write and graph an equation in two variables that shows the relationship between time and

distance

1 answer:

Mila [183]2 years ago

5 0

Answer:

what grade is this?

Step-by-step explanation:

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Trigonometry... hellpp plzzz

rjkz [21]

Answer:

17.1 degrees

Step-by-step explanation:

This is a tangent question because angle XYZ is adjacent to 13 and opposite of 4. This means that we will have to use opposite/adjacent. This is very simple if you know the formula. Just plug those numbers in to get 4/13 = 0.3076923076923077. However, now we need to find it in degrees. If you have an inverse calculator near you, you would plug it in to get about 17.10, which rounds to 17.1.

8 0

2 years ago

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What is the range of possible sizes for side x?

Murljashka [212]

Answer:

it might be 8-9.5 correct me if i am wrong

Step-by-step explanation:

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1 year ago

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Please answer!!!!!! will mark brainliest

timofeeve [1]

Answer:

The answer is 2/5 or 5.25

Step-by-step explanation:

5 sections so out of 5 and it said A or B so it is 2/5

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2 years ago

Suppose we roll a fair die and let X represent the number on the die. (a) Find the moment generating function of X. (b) Use the

Likurg_2 [28]

Answer:

(a) moment generating function for X is $\frac{1}{6}\left(e^{t}+e^{2 t}+e^{2 t}+e^{4 t}+e^{5 t}+e^{6 t}\right)$

(b) $\mathrm{E}(\mathrm{X})=\frac{21}{6} \text { and } E\left(X^{2}\right)=\frac{91}{6}$

Step-by step explanation:

Given X represents the number on die.

The possible outcomes of X are 1, 2, 3, 4, 5, 6.

For a fair die, $P(X)=\frac{1}{6}$

(a) Moment generating function can be written as $M_{x}(t)$ .

$M_x(t)=\sum_{x=1}^{6} P(X=x)$

$M_{x}(t)=\frac{1}{6} e^{t}+\frac{1}{6} e^{2 t}+\frac{1}{6} e^{3 t}+\frac{1}{6} e^{4 t}+\frac{1}{6} e^{5 t}+\frac{1}{6} e^{6 t}$

$M_x(t)=\frac{1}{6}\left(e^{t}+e^{2 t}+e^{3 t}+e^{4 t}+e^{5 t}+e^{6 t}\right)$

(b) Now, find $E(X) \text { and } E\((X^{2})$ using moment generating function

$M^{\prime}(t)=\frac{1}{6}\left(e^{t}+2 e^{2 t}+3 e^{3 t}+4 e^{4 t}+5 e^{5 t}+6 e^{6 t}\right)$

$M^{\prime}(0)=E(X)=\frac{1}{6}(1+2+3+4+5+6)$

$\Rightarrow E(X)=\frac{21}{6}$

$M^{\prime \prime}(t)=\frac{1}{6}\left(e^{t}+4 e^{2 t}+9 e^{3 t}+16 e^{4 t}+25 e^{5 t}+36 e^{6 t}\right)$

$M^{\prime \prime}(0)=E(X)=\frac{1}{6}(1+4+9+16+25+36)$

$\Rightarrow E\left(X^{2}\right)=\frac{91}{6}$

Hence, (a) moment generating function for X is $\frac{1}{6}\left(e^{t}+e^{2 t}+e^{3 t}+e^{4 t}+e^{5 t}+e^{6 t}\right)$ .

(b) $\mathrm{E}(\mathrm{X})=\frac{21}{6} \text { and } E\left(X^{2}\right)=\frac{91}{6}$

6 0

3 years ago

Simplify 2x + 5 +6x +3

bija089 [108]

Answer:

8x+8?

Step-by-step explanation:

2x+6x=8x

5+3=8

6 0

2 years ago