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kap26 [50]
3 years ago
9

2. How many moles of Na2CO3 are available?

Chemistry
1 answer:
Tanya [424]3 years ago
4 0

<em>malai</em><em> </em><em>aaudaina</em><em> </em><em>aati</em><em> </em><em>jabo</em><em> </em><em>tapai</em><em> </em>

<em>lai</em><em> </em><em>aaudaina</em><em> </em>

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stich3 [128]
What are the options?
4 0
3 years ago
A flask contains 5.0g of neon gas at a temperature of 35°C. The pressure gauge indicates 0.37atm inside the flask. What is the v
DaniilM [7]

Answer:

The volume of the neon gas is 17.07 L.

Explanation:

The ideal gas equation describes the relationship among the four variables  P, V, T, and n. An ideal gas<u> is a hypothetical gas whose pressure-volume-temperature  behavior can be completely accounted for by the ideal gas equation</u>.

In order to calculate the volume, first we need to convert the grams of neon to moles:

28.18 g Ne ------ 1 mol Ne

5.0 g Ne---------- <u>x= 0.25 mol Ne</u>

Now, using the ideal gas equation we calculate the volume:

pV= nRT

V= nRT ÷ p

V= (0.25 mol × 0.082 L.atm/mol.K × 308.15 K ÷ 0.37 atm

V= 17.07 L

6 0
3 years ago
What is the conecntration of Fe3 and the concentration of No3- present in the solution that result when 30.0 ml of 1.75M Fe(No3)
zvonat [6]

Answer:

[Fe^{+3}]=0.700 M

[NO_{3}^{-}]=2.10 M

Explanation:

Here, a solution of Fe(NO₃)₃ is diluted, as the total volume of the solution has increased. The formula for dilution of the compound is mathematically expressed as:

C_{1}. V_{1}= C_{2}.V_{2}

Here, C and V are the concentration and volume respectively. The numbers at the subscript denote the initial and final values. The concentration of Fe(NO₃)₃ is 1.75 M. As ferric nitrate dissociates completely in water, the initial concentration of ferric is also 1.75 M.

Solving for [Fe],

[Fe^{+3}]=\frac{C_{1}.V_{1}}{V_{2} }

[Fe^{+3}]=\frac{(1.75).(30.0)}{45.0+30.0 }

[Fe^{+3}]=0.700 M

For [NO₃⁻],

There are three moles of nitrate is 1 mole of Fe(NO₃)₃. This means that the initial concentration of nitrate ions will be three times the concentration of ferric nitrate i.e., it will be 5.25 M.

[NO_{3}^{-}]=\frac{C_{1}.V_{1}}{V_{2} }

[NO_{3}^{-}]=\frac{(5.25)(30.0)}{30.0+45.0 }

[NO_{3}^{-}]=2.10 M

7 0
3 years ago
What is the lewis dot structure for Cu2S​
Trava [24]

Answer:

LOL i belive its 200 because i did this exact same thing yesterday for homework and got it right so yeah, it should work. if it doesnt im sorry! but yeah XD sub to my yt channel too! DB_PLAYS <3

Explanation:

3 0
3 years ago
Read 2 more answers
How many moles of sodium, in 2.0 moles of sodium sulfate? Show all the work.
kiruha [24]
4 moles of sodium because you originally have 2.0 moles of Na2SO4 and you set that up at the beginning of the (what we called) train tracks. Then diagonally from that, on the bottom you put 1 mol of Na2SO4 to cancel the units. Then above that you have 2 moles of sodium because that is how many there are in the equation that they gave (the Na2 part). Then its just like a fraction, you multiply the top by the top and the bottom by the bottom, which would give you 4moles/1 or just 4 moles Na. I hope that helps
7 0
4 years ago
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