Answer:
3,833 for $28
2167 for $40
Step-by-step explanation:
Let X be the number of tickets sold at the price of $24, And Y be the number of tickets sold at the price of $40.
Now, $ 28X will be the revenue generated due to the $28 tickets
And, $40Y will be the revenue generated due to the 40$ tickets.
Now, Total revenue generated should be $194400.
Thus , 28X + 40Y = 194400 -(1).
Also,
Total number of seats in theater is 6000.
So, X + Y = 6000. -(2)
X = 6000 - Y.
Put in equation 1
We get , 168,000 - 28Y + 40Y = 194,400
12Y = 26,000
Y = 2,166.66
Since , Y is of 40 $ so minimum tickets sold should be 2167.
X = 3,833.
$117/1.9= $61.578 rounds to $61.60
$61.60 is the price before tax.
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Answer:
a) you are correct about a.
b)2/13 chance
c) 1/2 chance
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Answer:
Yes. The data provide enough evidence to support the claim that the mean weight of one-year-old boys is greater than 25 pounds.
P-value=P(t>2.84)=0.0024
Step-by-step explanation:
Hypothesis test on the population mean.
The claim is that the mean weight of one-year-old boys is greater than 25 pounds.
Then, the null and alternative hypothesis are:

The significance level is α=0.05.
The sample size is n=354. The sample mean is 25.8 pounds and the sample standard deviation is 5.3 pounds. As the population standard deviation is estimated from the sample standard deviation, we will use a t-statistic.
The degrees of freedom are:

The t-statistic is:

For a right tailed test and 353 degrees of freedom, the P-value is:

As the P-value is smaller than the significance level, the effect is significant and the null hypothesis is rejected.
There is enough evidence to support the claim that the mean weight of one-year-old boys is greater than 25 pounds.