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ella [17]
3 years ago
8

Consider the directed line segment from M(2,7) to (10,-4) points A,R and K are on MS​

Mathematics
1 answer:
german3 years ago
6 0

Answer:

Step-by-step explanation:

Input Data :

Point 1

(

x

A

,

y

A

)

= (0, 2)

Point 2

(

x

B

,

y

B

)

= (8, 8)

Objective :

Find what is a midpoint of a line segment?

Solution :

Midpoint  

(

x

M

,

y

M

)

=

(

x

A

+

x

B

2

,

y

A

+

y

B

2

)

=

(

0

+

8

2

,

2

+

8

2

)

=

(

8

2

,

10

2

)

Midpoint of a line segment  

(

x

M

,

y

M

)

= (4, 5)

hope that help

mark me brill

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slamgirl [31]

Answer:

b=-6\\c=7

Step-by-step explanation:

we know that

The general equation of a quadratic function in factored form is equal to

y=a(x-x_1)(x-x_2)

where

a is a coefficient of the leading term

x_1 and x_2 are the roots

we have

a=1\\x_1=3+\sqrt{2}\\x_2=3-\sqrt{2}

substitute

y=(1)(x-(3+\sqrt{2}))(x-(3-\sqrt{2}))

Applying the distributive property convert to expanded form

y=x^2-x(3-\sqrt{2})-x(3+\sqrt{2})+(3+\sqrt{2})(3-\sqrt{2})

y=x^2-(3x-x\sqrt{2})-(3x+x\sqrt{2})+(9-2)

y=x^2-3x+x\sqrt{2}-3x-x\sqrt{2}+7

y=x^2-6x+7

therefore

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6x − 3y = 7, −2x + y = −8 <br><br> x=?<br> y=?
kap26 [50]

Answer:

no solution

Step-by-step explanation:

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- 2x + y = - 8 → (2)

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- 6x + 3y = - 24 → (3)

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This indicates the system has no solution

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2 years ago
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