Yes because the fee will be $2×5(Days)=10 so she can still check out books but she can't have anymore late
Eight hundred seventy six thousand five hundred forty three.
<span>In the function "y=x2-18x" the goal is to find the value of the letter x. We know that y equals x2-18x. First, recognize that x2 is the same thing as 2x. So changing the problem to "y=2x-18x". We can subtract 18x from 2x, which leaves us with -16x. Now the problem looks like this: y=-16x. In order to get x by itself, we will need to do the same thing to both sides of the equation. In this case, we want the answer to be x by itself, or (1x) which is the same thing. We divide both sides of the equation by (-16). We are left with the following: y/-16=x. Basically, in words, x equals y divided by negative 16.</span>
33: 21 ...........................................
Answer:
![y = 34000(1-0.06) ^ t](https://tex.z-dn.net/?f=y%20%3D%2034000%281-0.06%29%20%5E%20t)
After 7.40 years it will be worth less than 21500
Step-by-step explanation:
This problem is solved using a compound interest function.
This function has the following formula:
![y = P(1-n) ^ t](https://tex.z-dn.net/?f=y%20%3D%20P%281-n%29%20%5E%20t)
Where:
P is the initial price = $ 34,000
n is the depreciation rate = 0.06
t is the elapsed time
The equation that models this situation is:
![y = 34000(1-0.06) ^ t](https://tex.z-dn.net/?f=y%20%3D%2034000%281-0.06%29%20%5E%20t)
Now we want to know after how many years the car is worth less than $ 21500.
Then we do y = $ 21,500. and we clear t.
![21500 = 34000(1-0.06) ^ t\\\\log(21500/34000) = tlog(1-0.06)\\\\t = \frac{log(21500/34000)}{log(1-0.06)}\\\\t = 7.40\ years.](https://tex.z-dn.net/?f=21500%20%3D%2034000%281-0.06%29%20%5E%20t%5C%5C%5C%5Clog%2821500%2F34000%29%20%3D%20tlog%281-0.06%29%5C%5C%5C%5Ct%20%3D%20%5Cfrac%7Blog%2821500%2F34000%29%7D%7Blog%281-0.06%29%7D%5C%5C%5C%5Ct%20%3D%207.40%5C%20years.)
After 7.40 years it will be worth less than 21500