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Kazeer [188]
2 years ago
13

absmiddle" class="latex-formula"> pls
Mathematics
1 answer:
morpeh [17]2 years ago
4 0

<h3>\frac{1}{1953125} ✅</h3>

\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\orange{:}}}}}

( { {5}^{3} })^{ - 3}  \\   \\ which\:means \:that \: {5}^{3}\:  is \:multiplied \:thrice\: with\: itself\\ \\ =  {5}^{3 \times  - 3}  \\ \\   =  {5}^{ - 9}  \\  \\=  \frac{1}{ {5}^{9} }  \\  \\  =  \frac{1}{5 \times 5 \times 5 \times 5 \times 5 \times 5 \times 5 \times 5 \times 5}  \\   \\ =  \frac{1}{1953125}

<u>Note</u>:-

( { {a}^{m} })^{n}  =  {a}^{m \times n}

{a}^{ - m}  =  \frac{1}{ {a}^{m} }

\large\mathfrak{{\pmb{\underline{\orange{Happy\:learning }}{\orange{!}}}}}

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Ted has a credit card that uses the average daily balance method. For the first 9 days of one of his billing cycles, his balance
slega [8]
Your question doesn't say what are the options, but we can make some reasoning.

The average daily balance method is based, obviously, on the <span>average daily balance, which is the average balance for every day of the billing cycle. Therefore, in order to calculate the average daily balance, you need to sum the balance of every day and then divide it by the days of the billing cycle.
In your case:
ADB = (9</span>×2030 + 21×1450) / 30 = 1624 $

Now, in order to calculate the interest, you should first calculate the daily rate, since APR is usually defined yearly, and therefore:
rate = 0.23 ÷ 365 = 0.00063 

Finally, the expression to calculate the interest could be:
interest = ADB × rate × days in the billing cycle
or else:
<span>interest = ADB × APR ÷ 365 × days in the billing cycle

In your case:
interest = 1624 </span>× 0.23 ÷ 365 × 30
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4 0
3 years ago
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The complement of set M is ______.
Firlakuza [10]

Answer:

M' is {-5, -4, -3, -2, -1, 0, 1, 3, 5, 6}

Step-by-step explanation:

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3 years ago
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likoan [24]
All of the x values are the same so it is not moving left or right.
The y values are changing by being 2 less than the original. 
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Which point would be a solution to the system of linear inequalities ?
brilliants [131]

Answer:

(12,-6)

Step-by-step explanation:

we have

y\leq \frac{4}{3}x+5 ----> inequality A

y\geq -\frac{5}{2}x+5 ---> inequality B

we know that

If a ordered pair is a solution of the system of inequalities, then the ordered pair must satisfy both inequalities (makes true both inequalities)

<u><em>Verify each point</em></u>

Substitute the value of x and the value of y  of each ordered pair in the inequality A and in the inequality B

case 1) (0,-1)

Inequality A

-1\leq \frac{4}{3}(0)+5

-1\leq5 ----> is true

Inequality B

-1\geq -\frac{5}{2}(0)+5

-1\geq 5 ----> is not true

therefore

The ordered pair is not a solution of the system

case 2) (0,3)

Inequality A

3\leq \frac{4}{3}(0)+5

3\leq5 ----> is true

Inequality B

3\geq -\frac{5}{2}(0)+5

3\geq 5 ----> is not true

therefore

The ordered pair is not a solution of the system

case 3) (-6,-6)

Inequality A

-6\leq \frac{4}{3}(-6)+5

-6\leq-3 ----> is true

Inequality B

-6\geq -\frac{5}{2}(-6)+5

-6\geq 20----> is not true

therefore

The ordered pair is not a solution of the system

case 4) (12,-6)

Inequality A

-6\leq \frac{4}{3}(12)+5

-6\leq21 ----> is true

Inequality B

-6\geq -\frac{5}{2}(12)+5

-6\geq -25 ----> is true

therefore

The ordered pair is a solution of the system (makes true both inequalities)

8 0
3 years ago
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