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V125BC [204]
3 years ago
9

1. Select all the equations where x = 5 is a solution.* A. 2x + 4 = 14 B. 5x = 55 C. 6x + 3 = 14 D. 8 + 3x = 23 E. 6x = 30 F. 5x

= 1​

Mathematics
1 answer:
aniked [119]3 years ago
7 0

Answer:

A,D,E. Hope this helps!

Step-by-step explanation:

A. x=5

B. x=11

C. x=11/6

D. x=5

E. x=5

F. x=1/5

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ANSWER

The required equation is:

9 {x}^{2}  - 25{y}^{2}  + 250y  - 85 0=0

EXPLANATION

The given equation is

9 {x}^{2}  - 25 {y}^{2}  = 225

Dividing through by 225 we obtain;

\frac{ {x}^{2} }{25}  -  \frac{ {y}^{2} }{9}  = 1

This is a hyperbola that has it's centre at the origin.

If this hyperbola is translated so that its center is now at (0,5).

Then its equation becomes:

\frac{ {(x - 0)}^{2} }{25}  -  \frac{ {(y - 5)}^{2} }{9}  = 1

We multiply through by 225 to get;

9 {x}^{2}  - 25( {y - 5})^{2}  = 225

We now expand to get;

9 {x}^{2}  - 25( {y}^{2} - 10y + 25 )= 225

9 {x}^{2}  - 25{y}^{2}  + 250y  - 6 25 = 225

The equation of the hyperbola in general form is

9 {x}^{2}  - 25{y}^{2}  + 250y  - 85 0=0

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