3 years ago

Please help! And 20 points! :3 I need help with these 3 questions- -3-||

Mathematics

1 answer:

BaLLatris [955]3 years ago

7 0

Answer:

where r the questions--?

Step-by-step explanation:

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What is the 4th term of the geometric sequence with <img src="https://tex.z-dn.net/?f=a_%7B1%7D" id="TexFormula1" title="a_{1}"

makvit [3.9K]

<u>Answer:</u>

The 4th term of the geometric sequence with = 5 and ratio (multiplier) = -3 is -135

<u>Solution:</u>

Given that, first term a of a G.P = 5 and common ratio ( r ) = -3 for an geometric progression.

We have to find the 4th term of the above given geometric progression

We know that, nth term of an G.P is given by

$t_{n}=a \cdot r^{n-1}$

So, now, 4th term is

$\begin{aligned} t_{4} &=5 \times(-3)^{4-1} \\ t_{4} &=5 \times(-3)^{3} \\ t_{4} &=5 \times(-27) \end{aligned}$

$t_{4}=-135$

hence, the 4th term of the given G.P is -135

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Answer:

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Step-by-step explanation:

75,000 * 4% is 3000

3000+ 75000

78000

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