Answer:
-11, -10, -9
Step-by-step explanation:
The middle one is their average, -30/3 = -10. The three integers are -11, -10, -9.
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I like to work "consecutive integer" problems using the average value of the integers involved. The average of <u>two</u> consecutive integers is 1/2 more than the small one, and 1/2 less than the large one, for example. Here, there are <u>three</u> consecutive integers, so their average is the middle one.
If you want to write that using an equation, you can let x represent the middle integer. Then the sum is ...
(x -1) +(x) + (x+1) = 3x = -30
x = -30/3 = -10 . . . . . the same average we computed above.
x -1 = -11 . . . . . the smaller of the other two integers
x +1 = -9 . . . . . the larger of the other two integers
Answer:
option C 13.5%
Step-by-step explanation:
As the heights of adults is normally distributed with mean=69 and standard deviation=2.5 so, the percent of men that are between 64 and 66.5 inches tall can be calculated as
P(64<X<66.5)=P[ (64-69)/2.5<(X-μ)/σ<(66.5-69)/2.5]
P(64<X<66.5)=P(-2<Z<-1)
P(64<X<66.5)=P(-2<Z<0)-P(-1<Z<0)
P(64<X<66.5)=0.4772-0.3413=0.1359
Thus, the percent of men are between 64 and 66.5 inches tall is 13.59%.
If we round the resultant quantity then it will be rounded to 13.6% but considering the given options, option C is most appropriate.
Answer:
The answer is AAS.
Step-by-step explanation:
Since you have 2 angles that are the same and 1 side which are the same or congruent.
A = E
and C=C they are vertical angles so they are the same
And the AB and ED side are also same.
-10x. All you have to do is subtract -2 from -8 and then put an x there so it’s -10x
Answer:
X= -11/6. Y=-40/9
Step-by-step explanation:
