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krok68 [10]
2 years ago
5

Given a triangle with verticies A(-3, 1), B(3,5), and C(5,-5). Vertify the midsegment theorem.

Mathematics
1 answer:
natima [27]2 years ago
3 0
And-6-4 abd (563-55 NDA fib
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6 divided by 2 and 1 fourths.<br> FULL ANSWER
enot [183]
6 divided by 2 and 1 forths is going to be 8 out of  3


4 0
3 years ago
Help me please and thank u
marin [14]

\large \mathfrak{Solution : }

As we know :

Dividend = Divisor × Quotient ( taking remainder as 0 )

So, Quotient = Dividend ÷ Divisor

by using the above relation we can say :

  • q = t ÷ 23

therefore, correct option is C. t ÷ 23

6 0
3 years ago
Use the polynomial 3x^2−4x^11+4x^4−2x^10−5+^8x^8 to answer the question. 
Anit [1.1K]

Answer: 11

<u>Step-by-step explanation:</u>

3x² - 4x¹¹ + 4x⁴ - 2x¹⁰ - 5 + 8x⁸

To find the degree, look for the largest exponent.  <em>11</em>

If you put this polynomial in standard form (from largest to smallest exponent), the first term will give you the degree of the polynomial and the leading coefficient.

- 4x¹¹ - 2x¹⁰ + 8x⁸ + 4x⁴ + 3x² - 5

4 0
3 years ago
Read 2 more answers
Will Upvote you!
notka56 [123]
For x = 4, then it means 3 to the fourth power or 3 times 3 times 3 times 3 times 3.  3^4 = 81 and 8 times that is 648.

y(x) = 8 * 3^x where x = 4:

y(x) = 8 * 3^4 = 8 * 81
y(x) = 648

The Function Rule then being that for every value of x there is one and only one value of y. y is the dependent variable and x is the independent variable.
7 0
3 years ago
If I wanted to estimate the √99, the first step would be to find the two squares that 99 lies on the numberline. I could then th
____ [38]

Answer:

Step-by-step explanation:

Smaller perfect squares near 99 is 81

Larger perfect square near 99 is 100

First step would be to find the two perfect squares that lies between on the number line. I could then think about the number 99 and how close it is to the smaller perfect square and the larger perfect square. That could tell me how far above or below the of the two perfect squares 99 lies on the number line. I could then take the square root of the perfect squares to see how I would estimate the square root of 99. The √99 is almost 10.

81 < 99 < 100

√81 < √99  < √100

8 < √99 < 10

So, √99 is almost 10.

8 0
1 year ago
Read 2 more answers
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