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krok68 [10]
3 years ago
5

Given a triangle with verticies A(-3, 1), B(3,5), and C(5,-5). Vertify the midsegment theorem.

Mathematics
1 answer:
natima [27]3 years ago
3 0
And-6-4 abd (563-55 NDA fib
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In the image, point A marks the center of the circle. Which two lengths must form a ratio of 1:2?
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Step-by-step explanation:

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Find the equation of the line using the point-slope formula. Write all the final equations
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Answer:

y=\frac{1}{2}x+\frac{5}{2}

Step-by-step explanation:

We are going to find the slope by lining up the points vertically and subtract, then put 2nd difference over first.

Also you could just use \frac{y_2-y_1}{x_2-x_1}.  It is the same thing.

(  5  ,   5)

-(  1  ,   3)

--------------

  4      2

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y-3=\frac{1}{2}(x-1)

We are going to solve this for y and simplify what we can because our goal is y=mx+b; this is slope-intercept form.  It is called that because it tells us the slope,m, and the y-intercept,b.

Distribute:

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Add 3 on both sides:

y=\frac{1}{2}x-\frac{1}{2}+3

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Answer:

x=10

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Thanks vro!

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