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ikadub [295]
3 years ago
9

Udsvb kbfnsdkmlfkmbn mk,dsldkfjvcxkm ,./ss.dskmcb nmld;s,fknvjf

Computers and Technology
1 answer:
Svetach [21]3 years ago
7 0

Answer:

not sure what language it is

Explanation:

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Which type of text may be formatted to print at the bottom of every page?
Tatiana [17]
The answer is header.
3 0
3 years ago
A maxillary partial denture will have a ____ connector, and the mandibular partial denture will have a ____ connector.
spayn [35]

The answer to the maxillary partial denture and the mandibular partial denture respectively are; Palatal connector and Lingual Connector

<h3>Understanding Dental Health</h3>

Maxillary partial denture is a dental prosthetic that allows for the placement of a series of artificial teeth in an area in the upper jaws where healthy teeth used to exist.

Meanwhile, Mandibular Partial Denture is a dental prosthetic that allows for the placement of a series of artificial teeth in an area in the lower jaws where healthy teeth used to exist.

Now, a maxillary partial denture has a palatal connector while a mandibular partial denture has a lingual connector.

Read more about dental health at; brainly.com/question/24345244

8 0
2 years ago
The int function can convert floating-point values to integers, and it performs rounding up/down as needed.
omeli [17]

Answer:

Thks is true the int function changes a float value to an integer and will round up or down by default.

5 0
3 years ago
In mathematics, "quadrant I" of the cartesian plane is the part of the plane where x and y are both positive. Given a variable,
lbvjy [14]

Answer:

#include <iostream>

using namespace std;

struct Cartesian {

double x;

double y;

};

int main() {

// creating a pointer p of type struct Cartesian

struct Cartesian *p = new Cartesian ;

cout << " Enter x: ";

// accessing the structure variable x by arrow "->"

cin >> p->x;

cout << "Enter y: ";

// accessing the structure variable y by arrow "->"

cin >> p->y;

// expression to check whether x and y lie in Quadrant 1

if (p->x > 0 && p->y > 0) {

 cout << "X and Y are in Quadrant 1 ";

}

else

{

 cout << "x And y are not in Quadrant 1";

}

// deleting the struct pointer p

delete p;

return 0;

}

Explanation:

in order to locate memory in heap, keyword "new" is used in C++ so,

struct Cartesian *p = new Cartesian ;

in order to access data members of the structure using pointer we always use an arrow "->". otherwise a dot oprerator is used to access data members.

in order to check whether x and y lie in 1st quadrent, we must use && operator in our if condition. so

if (p->x > 0 && p->y > 0)

&& will return true iff x and y both are +ve.

deleting the struct pointer p is important beacuse we are allocating memory in heap so heap memory should be used a resource and must be release when not needed otherwise it can cause memory leakage problems. so  

delete p;

5 0
3 years ago
In a linked chain implementation of a queue, the performance of the enqueue operation
alexdok [17]

Answer:

A.O(1)

Explanation:

In the implementation of queue by using linked chain the performance of  the enqueue operation is O(1).We have to  maintain  two pointers one  head and the other tailand  for  enqueue operation  we have to insert element  to the next of the tail and then  make that element  tail.Which takes O(1) time.

4 0
3 years ago
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