you've just posted only 1 question and the answer for that is option C.
thanks!
Answer:
Li₂SO₄ is the formed salt
Explanation:
We determine the reactants dissociations:
H₂SO₄ → 2H⁺ + SO₄⁻²
LiOH → Li⁺ + OH⁻
The 2H⁺ link the OH⁻ to form water, but there is one more H⁺, so we need another OH⁻ to finally produce 2 moles of H₂O
In conclussion to determine the lithium sulfate, which is the formed salt, Li will release 2 e⁻ as this equation shows:
2Li → 2Li⁺ + 2e⁻
Now the neutralization reaction is:
2LiOH + H₂SO₄ → Li₂SO₄ + 2H₂O
Answer:
It should be transferred to a Beaker to finish preparing the solution
Explanation:
NaNO₃ is sodium Nitrate. It is a salt that is soluble in water hence it's aqueous solution can be prepared by dissolving it in water.
A beaker is a laboratory glassware that is used for various functions; one of which includes the preparation of reagents or aqueous solutions of a compound. In the example narrated in the question, the measured NaNO₃ solid can be transferred to a 100 mL or 200 mL beaker and then added to it is the desired volume of water to make the solution 100 mL. This solution can then be stirred with a "glass rod"
