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nevsk [136]
3 years ago
6

Acetylene is the substance burned in oxy-acetylene torches. Write a balanced equation for the complete oxidation reaction that o

ccurs when acetylene (C2H2) burns in air. Use the smallest possible integer coefficients.
Chemistry
1 answer:
nexus9112 [7]3 years ago
4 0

Answer: 2C_2H_2+5O_2\rightarrow 4CO_2+2H_2O

Explanation:

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products must be same as the mass of reactants.

For the conservation of mass, the number of atoms of each element must be same in reactants and products. Thus we need to balance the reaction by writing appropriate stochiometric coefficients.

All the hydrocarbons burn in oxygen to form carbon dioxide and water.Thus the complete balanced equation is:

2C_2H_2+5O_2\rightarrow 4CO_2+2H_2O

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In a test of an automobile engine 1.00 L of octane (702 g) is burned, but only 1.84 kg of carbon dioxide is produced. What is th
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Answer:

The % yield of CO2 is 85.05 %

Explanation:

Step 1: Data given

Mass of octane = 702 grams

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Molar mass of CO2

Step 2: The balanced equation

2C8H18 + 25O2 → 16CO2 + 18H2O

Step 3: Calculate moles of octane

Moles octane = mass octane / molar mass octane

Moles octane = 702.0 grams / 114.23 g/mol

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Step 4: Calculate moles of CO2

For 2 moles octane we need 25 moles O2 to produce 16 moles CO2 and 18 moles H2O

For 6.145 moles octane we'll have 8*6.145 moles =49.16 moles

Step 5: Calculate mass of CO2

Mass CO2 = moles CO2 * molar mass CO2

Mass CO2 = 49.16 moles * 44.01 g/mol

Mass CO2 = 2163.5 grams

Step 6: Calculate % yield of carbon dioxide

% yield = (actual yield / theoretical yield)*100%

% yield = (1840/2163.5)*100%

% yield = 85.05 %

The % yield of CO2 is 85.05 %

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EXPLANATION:

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3 years ago
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