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nevsk [136]
2 years ago
6

Acetylene is the substance burned in oxy-acetylene torches. Write a balanced equation for the complete oxidation reaction that o

ccurs when acetylene (C2H2) burns in air. Use the smallest possible integer coefficients.
Chemistry
1 answer:
nexus9112 [7]2 years ago
4 0

Answer: 2C_2H_2+5O_2\rightarrow 4CO_2+2H_2O

Explanation:

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products must be same as the mass of reactants.

For the conservation of mass, the number of atoms of each element must be same in reactants and products. Thus we need to balance the reaction by writing appropriate stochiometric coefficients.

All the hydrocarbons burn in oxygen to form carbon dioxide and water.Thus the complete balanced equation is:

2C_2H_2+5O_2\rightarrow 4CO_2+2H_2O

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a sample of 25.0g of an unknown metal is added to 25.0ml of water in a graduated cylinder and the final volume is 28.5ml what is
leva [86]

Answer:

<h2>The answer is 7.14 g/mL</h2>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume}  \\

From the question

mass of metal = 25 g

volume = final volume of water - initial volume of water

volume = 28.5 - 25 = 3.5 mL

It's density is

density =  \frac{25}{3.5}  \\  = 7.142857...

We have the final answer as

<h3>7.14 g/mL</h3>

Hope this helps you

8 0
3 years ago
Which type of disease is caused by pathogens?<br><br> a(n) <br> disease
Lerok [7]
Sorry I’m just here for more questions
4 0
2 years ago
Methane burns in the presence of oxygen to form carbon dioxide and water.
wlad13 [49]

Answer:

= 9.28 g CO₂

Explanation:

First write a balanced equation:

CH₄ + 2O₂ -> 2H₂O + CO₂

Convert the information to moles

7.50g CH₄ = 0.46875 mol CH₄

13.5g O₂ = 0.421875 mol O₂

Theoretical molar ratio CH₄:O₂ -> 1:2

Actual ratio is  0.46875 : 0.421875 ≈ 1:1

If all CH₄ is used up, there would need to be more O₂

So O₂ is the limiting reactant and we use this in our equation

Use molar ratio to find moles of CO₂

0.421875 mol O₂ * 1 mol CO₂/2 mol O₂=0.2109375 mol CO₂

Then convert to grams

0.2109375 mol CO₂ = 9.28114 g CO₂

round to 3 sig figs

= 9.28 g CO₂

5 0
3 years ago
Elements that exceed the octet rule must have an _______________. unoccupied s-orbital unoccupied p-orbital unoccupied d-orbital
Irina18 [472]
Elements that exceed the octet rule must have an unoccupied d orbital. I believe.
7 0
3 years ago
A solution was found to have a 15.6 % transmittance at 500 nm, its wavelength of maximum absorption, using a cell with a path le
Gnesinka [82]

For the absorbance of the solution in a 1.00 cm cell at 500 nm  is mathematically given as

A’ = 0.16138

<h3>What is the absorbance of the solution in a 1.00 cm cell at 500 nm?</h3>

Absorbance (A) 2 – log (%T) = 2 – log (15.6) = 0.8069

Generally, the equation for the Beer’s law is mathematically given as

A = ε*c*l

0.8069 = ε*c*(5.00 )

ε*c = 0.16138 cm-1

then for when ε*c is constant

l’ = 1.00

A’ = (0.16138 cm-1)*(1.00 cm)

A’ = 0.16138

In conclusion, the absorbance of the solution in a 1.00 cm cell at 500 nm is

A’ = 0.16138

Read more about Wavelength

brainly.com/question/3004869

7 0
2 years ago
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