The distance from friend's village to Lucas's house is 45 miles
Step-by-step explanation:
Lets assume the distance from Lucas home to friend's village is x miles
The time taken to cycle from Lucas home to friend's village is 3 hrs....t₁
The time taken if travelling at a 5 mph reduced speed is 1.5 hrs longer......t₂
t₂=4.5 hrs
t₁= 3 hrs
Speed for cycle in first instance, where t₁=3 hrs and distance is x miles
s₁=d/t = x/3 mph
Speed for cycle if travelling at a slower speed,
Time taken in the second instance when travelling at a slower speed
=
The distance from friend's village to Lucas's house is 45 miles
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Formula for speed:brainly.com/question/13664094
Keywords: cycle,home, village, travels,slower,longer
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We are asked to find the G.C.F. of 8x-6.
- G.C.F. stands for Greatest Common Factor.
So what is the G.C.F. of 8x-6? We can list all of their common factors and then select the greatest one, like so:
1, 2, 4, 8, x
-1, 1, 2, -3, 3, -6, 6
So the GCF is:
2
Now, we can also factor it out by placing it outside the parentheses ():
2(4x-3)
See, we factored it out by dividing both terms of the expression by the G.C.F.
Remember this...
Hope this helps you out! :D
Ask in comments if any queries arise.
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Answer:
Both fireworks will explode after 1 seconds after firework b launches.
Step-by-step explanation:
Given:
Speed of fire work A= 300 ft/s
Speed of Firework B=240 ft/s
Time before which fire work b is launched =0.25s
To Find:
How many seconds after firework b launches will both fireworks explode=?
Solution:
Let t be the time(seconds) after which both the fireworks explode.
By the time the firework a has been launched, Firework B has been launch 0.25 s, So we can treat them as two separate equation
Firework A= 330(t)
Firework B=240(t)+240(0.25)
Since we need to know the same time after which they explode, we can equate both the equations
330(t) = 240(t)+240(0.25)
300(t)= 240(t)+60
300(t)-240(t)= 60
60(t)=60
t=1
Answer:
32.5%
Step-by-step explanation:
first we will have to calculate how much miles the car traveled, to do that we will multiply the speed by hour long the car was traveling for which is
65*3=195
During those 195 miles the car used 1 gallon for every 30 miles which means it used 6.5 gallons of its tank
195/30=6.5
6.5 gallons is 32.5% of 20 gallons
6.5/20=0.325
0.325 * 100 = 32.5%
1.)
-x=3-4x+6
3x=3+6
3x=9
X=3
c
2.)
-6+x=-2
x=4
B
