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Dima020 [189]
3 years ago
6

A football player kicks a ball with a mass of .55 kg. The average acceleration of the football was 14.9 m/s2. How much force did

the kicker supply to the football?
A. 35.24 N

B. 8.2 N

C. 35.24 m/s^2

D. 8.2 m/s^2
Physics
1 answer:
algol133 years ago
8 0

Answer:8.2N

Explanation:I did the quiz on k12 and that’s the answer i got :)

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A 3-kg ball is thrown with a speed of 8 m/s at an unknown angle above the horizontal. The ball attains a maximum height of 2.8 m
Alina [70]

Answer:

13.5 J

Explanation:

mass of ball, m = 3 kg

maximum height, h = 2.8 m

initial speed, u = 8 m/ s

Angle of projection, θ

use the formula of maximum height

H = \frac{u^{2}Sin^{2}\theta }{2g}

2.8 = \frac{8^{2}Sin^{2}\theta }{2\times 9.8}

Sin θ = 0.926

θ = 67.8°

The velocity at maximum height is u Cosθ = 8 Cos 67.8 = 3 m/s

So, kinetic energy at maximum height

K=\frac{1}{2}mv^{2}

K = 0.5 x 3 x 3 x 3

K = 13.5 J

8 0
4 years ago
When populations of two species work together to obtain resources, they are
valina [46]
<span>cooperation. i think that is it

</span>
7 0
3 years ago
Read 2 more answers
1) How much work is done when a force of 50N<br> pulls a wagon 20 meters?
katrin2010 [14]

Answer:

100J

Explanation:

50N*20m=100J

N*m=J(joule)

4 0
3 years ago
If the two blocks are moving to the right at constant velocity, A. the horizontal force that B exerts on A points to the left. B
RSB [31]

Answer:

D. not enough information to decide

Explanation:

i dont understand >.<

7 0
3 years ago
Atomic hydrogen produces a well-known series of spectral lines in several regions of the electromagnetic spectrum. Each series f
navik [9.2K]

Answer:

n₁ = 3

Explanation:

The energy of the states in the hydrogen atom is explained by the Bohr model, the transitions heal when an electron passes from a state of higher energy to another of lower energy,

       ΔE = E_{nf} - E₀ = - k²e² / 2m (1 / n_{f}²2 - 1 / n₀²)

The energy of this transition is given by the Planck equation

       E = h f = h c / λ

       h c / λ = -k²e² / 2m (1 / no ²- 1 / no²)

       1 / λ = Ry (1/ n_{f}² - 1 / n₀²)

Let's apply these equations to our case

     λ = 821 nm = 821 10⁻⁹ m

     E = h c / λ

     E = 6.63 10⁻³⁴ 3 10⁸/821 10⁻⁹

     E = 2.423 10⁻¹⁹ J

Now we can use the Bohr equation

Let's reduce to eV

       E = 2,423 10⁻¹⁹ J (1eV / 1.6 10⁻¹⁹) = 1,514 eV

       E_{nf} - E₀ = -13.606 (1 /  n_{f}² - 1 / n₀²)   [eV]

Let's look for the energy of some levels

n         E_{n} (eV)          E_{nf} - EE_{ni} (eV)

1         -13,606           E₂-E₁ = 10.20

2        -3.4015           E₃-E₂ = 1.89

3        -1.512              E₄- E₃ = 0.662

4        -0.850375

We see the lines of greatest energy for each possible series, the closest to our transition is n₁ = 3 in which a transition from infinity (n = inf) to this level has an energy of 1,512 eV that is very close to the given value

8 0
3 years ago
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