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valentina_108 [34]
3 years ago
12

a golf club is swung and strikes a golf ball with a force of 12.2 N. The golf ball accelerates at 265.2 m/s2. Calculate the mass

of the golf ball. Show your work and include the correct unit.
Physics
1 answer:
MaRussiya [10]3 years ago
5 0

Answer:

0.046\ kg

Explanation:

We\ are\ given\ that,\\Acceleration\ produced\ on\ the\ golf\ ball\ due\ to\ Force\ exerted=265.2\ m/s^2\\Magnitude\ of\ the\ Force\ exerted\ over\ the\ Golf-Ball=12.2\ N\\We\ know\ that,\\'The\ force\ acting\ on\ an\ object\ is\ equivalent\ to\ the\ product\ of\ it's\ mass\\ and\ the\ acceleration\ produced'.\\Or,\\F=ma\\Let\ the\ mass\ of\ the\ golf\ ball\ be\ m,\\Hence,\\12.2=265.2\ m\\m=\frac{12.2}{265.2}=0.046\ kg

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Explanation:

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The elevation is 10 [m], and at this point the ball is having only potential energy, the kinetic energy is zero.

E_{p} =m*g*h\\where:\\g= gravity[m/s^{2} ]\\m = mass [kg]\\m= \frac{E_{p} }{g*h}\\ m= \frac{100}{9.81*10}\\\\m= 1.01[kg]\\\\

In the moment when the ball starts to fall, it will lose potential energy and the potential energy will be transforme in kinetic energy.

When the elevation is 5 [m], we have a potential energy of

P_{e} =m*g*h\\P_{e} =1.01*9.81*5\\\\P_{e} = 50 [J]\\

This energy is equal to the kinetic energy, therefore

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