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s344n2d4d5 [400]
3 years ago
10

A 0.40 kg toy car moves at constant acceleration of 2.3 m/s2. determine the net applied force that is responsible for that accel

eration.
Physics
2 answers:
GREYUIT [131]3 years ago
5 0
Net force = ma = 0.4x2.3 =0.92N.
snow_lady [41]3 years ago
5 0

Answer:

F = 0.92 N

Explanation:

It is given that,

Mass of the toy car, m = 0.4 kg

Acceleration of the car, a=2.3\ m/s^2

Let F is the net force applied to the to the toy car. It is equal to the product of mass and acceleration. Its formula is given by :

F=m\times a

F=0.4\ kg\times 2.3\ m/s^2

F = 0.92 N

So, the net applied force that is responsible for that acceleration is 0.92 N. Hence, this is the required solution.

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Answer:

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Explanation:

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28km/h

Hopefully this helps you :)

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Answer:

3,237.78N

Explanation:

According to Newton's second law of motion

F = mass * acceleration

Since a = v-u/t

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v = 50.0m/s

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Substitute

F = 0.155(50-(-44))/0.00450

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F = 14.57/0.00450

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