13500 m in 250 s
s is the second rate
deomenator is bottom number in a/b, denomenator is b
13500m/250s
use clculator or something to divide or use head
54m/s
answer is A
Number x percent turned into decimal
39 x 0.666666666 = 26
Answer:
We are 95% confident that the true proportion of TV audience is between 65.15% and 65.85%
Step-by-step explanation:
-From the given information,
.
-We calculate the confidence interval using this value at 95% confidence level:
![CI=\hat p\pm z \sqrt{\frac{\hat p(1-\hat p)}{n}}\\\\\\=0.65\pm 1.96\times \sqrt{\frac{0.65\times 0.35}{12000}}\\\\\\=0.65\pm 0.0085\\\\\\=[0.6415,0.6585]](https://tex.z-dn.net/?f=CI%3D%5Chat%20p%5Cpm%20z%20%5Csqrt%7B%5Cfrac%7B%5Chat%20p%281-%5Chat%20p%29%7D%7Bn%7D%7D%5C%5C%5C%5C%5C%5C%3D0.65%5Cpm%201.96%5Ctimes%20%5Csqrt%7B%5Cfrac%7B0.65%5Ctimes%200.35%7D%7B12000%7D%7D%5C%5C%5C%5C%5C%5C%3D0.65%5Cpm%200.0085%5C%5C%5C%5C%5C%5C%3D%5B0.6415%2C0.6585%5D)
So, the 95% confidence interval is (0.6515,0.6585).
Hence, we are 95% confident that the true proportion of TV audience is between 65.15% and 65.85%.
First compute the coefficient like this:

Simplifying the fraction over 4! we get:

and the variables are

. So answer

.
The correct answer is C then.
Answer:
1115322
Step-by-step explanation:
In 1906, San Francisco felt the impact of an earthquake with a magnitude of 7.8.
Claimed statement is he worst is yet to come, with an earthquake 142,990 times as intense as the 1906 earthquake ready to hit San Francisco.
We need to find the magnitude of their claimed earthquake.
It can be calculated by simply multiplying 142,990 by 7.8 as follows :

The magnitude of claimed earthquake is 1115322
.