Use properties of addition to evaluate the expression. −35+7+(−15) Enter your answer in the box.

Please answer ASAP! The number 650,000 written in scientific notation would be _____.

AfilCa [17]

Answer:

65x10^5

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

A store has apples on sale at $3.00 for 2 pounds.

sergeinik [125]

5 ounces × 24 apples= 120 ounces of apples

1 pound= 16 ounces

120 ounces = 7.5 pounds

$3 = 2 pounds

$11.25 = 7.5 pounds.

You cannot but 24 apples for $9 because each apple is five ounces, so you multiply each apple by its weight, and get 120 ounces. Since there is 16 ounces in 1 pound, you have 7.5 pounds of apples. If 2 pounds is three dollars then 7.5 can't be nine.

4 0

3 years ago

There are 107 coins in a jar, all dimes and nickels. The coins are worth $6.70. How many of each kind of

weqwewe [10]

d = number of dimes

n = number of nickels

The jar contains a total of 107 coins, so

d + n = 107

Each dime is worth $0.10 and each nickel is worth $0.05, and the jar contains a total value of $6.70, so

0.10d + 0.05n = 6.70

Multiply both sides of the second equation by 100 to eliminate the decimal points:

10d + 5n = 670

Multiply both sides of the first equation by -5:

-5d - 5n = -535

Add the corresponding sides of these two equations to eliminate n and solve for d :

(10d + 5n) + (-5d - 5n) = 670 + (-535)

(10 - 5)d + (5 - 5)n = 670 - 535

5d = 135

d = 135/5 = 27

Then

n = 107 - d = 80

so the jar contains 27 dimes and 80 nickels.

7 0

3 years ago

It is possible to score higher than 1600 on the combined mathematics and reading portions of the SAT, but scores 1600 and above

Citrus2011 [14]

Answer:

The proportion of scores reported as 1600 is 0.0032

Step-by-step explanation:

Let X be the score for 1 random person in SAT combining maths and reading. X has distribution approximately N(μ = 1011,σ = 216).

In order to make computations, we standarize X to obtain a random variable W with distribution approximately N(0,1)

$W = \frac{X-\mu}{\sigma} = \frac{X-1011}{216} \simeq N(0,1)$

The values of the cummulative distribution function of the standard Normal random variable, lets denote it $\phi$ are tabulated, you can find those values in the attached file. Now, we are ready to compute the probability of X being bigger than 1600